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Anestetic [448]
3 years ago
15

I need help asap I will mark branlist

Mathematics
1 answer:
worty [1.4K]3 years ago
7 0

Least to greatest would be 14,000; 43,043; 143,431; 342,143. The answer would be D. If this is right could you possibly give me brainliest? Hope this helped.

You might be interested in
4y+x+9 well its making me wrote 20 charcters sooooooooooo
hodyreva [135]

               4y + x + 9

can't be simplified, factored, expanded, graphed, solved, or evaluated.
So what is your question ?


3 0
3 years ago
Because of safety considerations, in May 2003 the Federal Aviation Administration (FAA) changed its guidelines for how small com
Ymorist [56]

Answer:

a) 183-1.984\frac{20}{\sqrt{100}}=179.032    

183+1.984\frac{20}{\sqrt{100}}=186.968    

So on this case the 95% confidence interval would be given by (179.032;186.968)    

b) 190-1.984\frac{23}{\sqrt{100}}=185.437    

190+1.984\frac{23}{\sqrt{100}}=194.563    

So on this case the 95% confidence interval would be given by (185.437;194.563)    

c) For Summer the confidence interval was (179.032;186.968) and as we can see our upper limit is <190 so then we can conclude that they are below the specification of 190 at 5% of significance

For Winter the confidence interval was (185.437;194.563) and again the upper limit is <190 so then we can conclude that they are below the specification of 195 at 5% of significance

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

Part a : Summer

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=100-1=99

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,99)".And we see that t_{\alpha/2}=1.984

Now we have everything in order to replace into formula (1):

183-1.984\frac{20}{\sqrt{100}}=179.032    

183+1.984\frac{20}{\sqrt{100}}=186.968    

So on this case the 95% confidence interval would be given by (179.032;186.968)    

Part b: Winter

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=100-1=99

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,99)".And we see that t_{\alpha/2}=1.984

Now we have everything in order to replace into formula (1):

190-1.984\frac{23}{\sqrt{100}}=185.437    

190+1.984\frac{23}{\sqrt{100}}=194.563    

So on this case the 95% confidence interval would be given by (185.437;194.563)    

Part c

For Summer the confidence interval was (179.032;186.968) and as we can see our upper limit is <190 so then we can conclude that they are below the specification of 190 at 5% of significance

For Winter the confidence interval was (185.437;194.563) and again the upper limit is <190 so then we can conclude that they are below the specification of 195 at 5% of significance

5 0
3 years ago
A certain school district has specified 5 different novels and 4 different non-fiction books from which teachers can choose to a
shutvik [7]

Answer:

There are 60 different summer reading lists possible.

Step-by-step explanation:

A certain school district has specified 5 different novels and 4 different non-fiction.

Each summer reading list must have exactly 3 novels and 2 non-fiction books.

So, the number of different summer reading lists that are possible is given by:

5C3\times 4C2

= \frac{5!}{3!2!} \times\frac{4!}{2!2!}

= 10\times6=60

Hence, there are 60 different summer reading lists possible.

5 0
3 years ago
I forgot how to do this. Can someone tell me how?
Katyanochek1 [597]
Hey there, CrisisOnCats!

Absolute value is when any value that's inside the box, positive or negative, will always come out as positive.
For this one, you solve it as a normal equation, solving for x.
So, 8 = 5 - x
8-5 = 5-5 - x
3 = -x
x = -3
One value can be -3
To find the other value, just find any value that's equal to 8 when added or subtracted from 5, negative or positive.
We have 13 in this case.
5 - 13 is equals to -8 but since it's absolute value, it would be positive 8.
So, the answer is D

Thank you for using Brainly.
See you soon!
7 0
3 years ago
Read 2 more answers
Combine like terms -2xy+2xy+3xy
liberstina [14]

Answer:

3xy

Step-by-step explanation:

These terms are all like terms so you can add:

-2xy + 2xy = <em>0xy</em>

Now add 3xy + 0xy: 3xy

3 0
3 years ago
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