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Ilya [14]
4 years ago
13

What is an equation of the line perpendicular to y=-2x-2 and through (-2,4)

Mathematics
1 answer:
zheka24 [161]4 years ago
8 0

Let k:y=m_1x+b_1 and l:y=m_2x+b_2

l\ \perp\ k\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}

We have

y=-2x-2\to m_1=-2

Therefore

m_2=-\dfrac{1}{-2}=\dfrac{1}{2}

We have the equation of a line:

y=\dfrac{1}{2}x+b

Put the coordinates of the point (-2, 4) to the equation of a line:

4=\dfrac{1}{2}(-2)+b

4=-1+b      <em>add 1 to both sides</em>

5=b\to b=5

Answer: \boxed{y=\dfrac{1}{2}x+5}

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