All categories

2 years ago

What is the circumference of a circle with a radius of 6?

Mathematics

2 answers:

Natali5045456 [20]2 years ago

8 0

The circumference is 37.7
hope it helps:)

koban [17]2 years ago

3 0

Answer:

37.68 or 12π

Step-by-step explanation:

C = 2πr

C = 2(3.14)6 = 37.68

You might be interested in

Name the place value to which each number was rounded 7.429 to 7.4

alexgriva [62]

Answer:

tenths place

Step-by-step explanation:

1/10=0.1 ==> one-tenth

4 0

1 year ago

Jimmy ran 3 miles west from home and then turned north and jogged 4 miles. In a straight line, how far is Jimmy from home?

Anit [1.1K]

In a straight line jimmy is 5 miles far

5 0

2 years ago

Read 2 more answers

The Suarez family paid $16.50 for 3 movie tickets. How much would they have paid for 12 tickets?

Dominik [7]

Answer:

It will cost 66 dollars for 12 tickets

Step-by-step explanation:

We can write a ratio to solve.

16.50 x

-------- = ----------

3 12

Using cross products

12 * 16.50 = 3x

198 = 3x

66 = x

It will cost 66 dollars for 12 tickets

3 0

2 years ago

In a certain Algebra 2 class of 29 students, 7 of them play basketball and 24 of them play baseball. There are 3 students who pl

antiseptic1488 [7]

Answer:

$\frac{5}{29}$

Step-by-step explanation:

Let $n(A)$ represent students playing basketball, $n(B)$ represent students playing baseball.

Then, $n(A)=7$ , $n(B)=24$

Let $n(S)$ be the total number of students. So, $n(S)=29$ .

Now,

$P(A)=\frac{n(A)}{n(S)}=\frac{7}{29}$

$P(B)=\frac{n(B)}{n(S)}=\frac{24}{29}$

3 students play neither of the sport. So, students playing either of the two sports is given as:

$n(A\cup B)=n(S)-3\\n(A\cup B)=29-3=26$

∴ $P(A\cup B)=\frac{n(A\cup B)}{n(S)}=\frac{26}{29}$

From the probability addition theorem,

$P(A\cup B)=P(A)+P(B)-P(A\cap B)$

Where, $P(A\cap B)$ is the probability that a student chosen randomly from the class plays both basketball and baseball.

Plug in all the values and solve for $P(A\cap B)$ . This gives,

$\frac{26}{29}=\frac{7}{29}+\frac{24}{29}+P(A\cap B)\\\\\frac{26}{29}=\frac{7+24}{29}+P(A\cap B)\\\\\frac{26}{29}=\frac{31}{29}+P(A\cap B)\\\\P(A\cap B=\frac{31}{29}-\frac{26}{29}\\\\P(A\cap B=\frac{31-26}{29}=\frac{5}{29}$

Therefore, the probability that a student chosen randomly from the class plays both basketball and baseball is $\frac{5}{29}$

6 0

2 years ago

What value is added to both sides of the equation x2 - 8x = -10 in order to solve by completing the square?

IgorLugansk [536]

X² - 8x = -10

to have a complete square, we must have this format:

a² + 2ab + b²

a² = x²
2ab = -8x ⇒ 2(x)(-4)
b² = -4² = 16

x² - 8x + 16 = -10 + 16
x² - 8x + 16 = +6
(x-4)² - 6 = 0

Both sides must have an additional value of 16.

5 0

2 years ago