Two passenger trains traveling in opposite directions meet and pass each other. Each train is 1/12 miles long and is traveling 5
0 mph. How many seconds after the front cars of the trains meet will their rear cars pass each other?
1 answer:
Answer:
6 seconds
Step-by-step explanation:
1/12 mile * 5280 feet/mile = 440 feet per train
50 miles/hour * 1/3600 hr/sec * 5280 ft/mile = 73 1/3 ft/second
one train has to travel 440 feet to pass the other train
440 feet * 1/(73 1/3) sec/ft = 6 seconds
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