X-2.13=5.3 x= 5.3 + 2.13 x = 7.43
+2.13
Process:
Start by isolating the variable by itself, in this case we add 2.13 to the -2.13 as whatever we do to one side of the equation we do to the other hence we add 2.13 to 5.3 which will become x = 7.43 and we can verify our answer by substituting our answer for x
7.43 - 2.13 = 5.3
Answer:
The largest total area that can be enclosed will be a square of length 272 yards.
Step-by-step explanation:
First we get the perimeter of the large rectangular enclosure.
Perimeter of a rectangle =2(l + w)
Perimeter of the large rectangular enclosure= 1088 yard
Therefore:
2(L+W)=1088
The region inside the fence is the area
Area: A = LW
We need to solve the perimeter formula for either the length or width.
2L+ 2W= 1088 yd
2W= 1088– 2L
W = 
W = 544–L
Now substitute W = 544–L into the area formula
A = LW
A = L(544 – L)
A = 544L–L²
Since A is a quadratic expression, we re-write the expression with the exponents in descending order.
A = –L²+544L
Next, we look for the value of the x coordinate


L=272 yards
Plugging L=272 yards into the calculation for area:
A = –L²+544L
A(272)=-272²+544(272)
=73984 square yards
Thus the largest area that could be encompassed would be a square where each side has a length of 272 yards and a width of:
W = 544 – L
= 544 – 272
= 272 yards
Hi. Here are the answers and I am attaching a file that shows how I got them.
1. The simplified answer is: -5/12
2. The simplified answer is: - 1 1/5
3. The simplified answer is: - 1 7/10
4. The simplified answer is: 1 5/6
5. The simplified answer is: 1 2/3
Hope this helps.
Take care,
Diana