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IgorLugansk [536]
3 years ago
15

Solve for u. 36 – 9u = 27

Mathematics
1 answer:
strojnjashka [21]3 years ago
8 0

Answer:

u = 1

Step-by-step explanation:

First, we can use inverse operations to help.

27 + 9u = 36

Next, we can start replacing u with numbers to find which number fits in u.

27 + 9(1) = 36

27 + 9(2) ≠ 36

27 + 9(3) ≠ 36

Now, we know that u = 1

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20p + -5p - -17 = -13 

20p + -5p - -17 = -13:p  |Solve \  for \ p| 

20p-5p+17=-13 


15p+17=-13
 
 


15p=-13-17
 
  |Subtract \ 17 \ from \ both \ sides| 


15p=-30
 
 


15p/15=-30/15
 
  |Divide  \ both \ sides \ by \ 15| 


p=-2
 

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Step-by-step explanation:

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3 years ago
Determine all real values of p such that the set of all linear combination of u = (3, p) and v = (1, 2) is all of R2. Justify yo
Rama09 [41]

Answer:

p ∈ IR - {6}

Step-by-step explanation:

The set of all linear combination of two vectors ''u'' and ''v'' that belong to R2

is all R2 ⇔

u\neq 0_{R2}      

v\neq 0_{R2}

And also u and v must be linearly independent.

In order to achieve the final condition, we can make a matrix that belongs to R^{2x2} using the vectors ''u'' and ''v'' to form its columns, and next calculate the determinant. Finally, we will need that this determinant must be different to zero.

Let's make the matrix :

A=\left[\begin{array}{cc}3&1&p&2\end{array}\right]

We used the first vector ''u'' as the first column of the matrix A

We used the  second vector ''v'' as the second column of the matrix A

The determinant of the matrix ''A'' is

Det(A)=6-p

We need this determinant to be different to zero

6-p\neq 0

p\neq 6

The only restriction in order to the set of all linear combination of ''u'' and ''v'' to be R2 is that p\neq 6

We can write : p ∈ IR - {6}

Notice that is p=6 ⇒

u=(3,6)

v=(1,2)

If we write 3v=3(1,2)=(3,6)=u , the vectors ''u'' and ''v'' wouldn't be linearly independent and therefore the set of all linear combination of ''u'' and ''b'' wouldn't be R2.

7 0
3 years ago
If a bus leaves every 8 minutes and a other bus leaves every 10 how often will both buses leave at the same time
olga nikolaevna [1]

Answer:

i think its 10:00am

Step-by-step explanation:

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