See photo for drawing.
Words:
Suppose a square is 100%,
50%: the square is divided into two equal parts, and one of them is shaded, therefore it is 50%.
25%: the square is divided into 4 equal parts, and one of them is shaded, therefore it is 25%.
150%: there are two squares, each divided into 2 equal parts, and 3 of them is shadowed, therefore it is 150%.
Well, it should be 45 because 1/3 of the game would be 15 and 15+15 is 30 (2/3rds cost), so 15+15+15, 45, would be the full cost of the game
Answer:
f(7) = - 25
Step-by-step explanation:
To evaluate f(7) substitute x = 7 into f(x), that is
f(7) = - 5(7) + 10 = - 35 + 10 = - 25
Answer:
<em>The answers are for option (a) 0.2070 (b)0.3798 (c) 0.3938
</em>
Step-by-step explanation:
<em>Given:</em>
<em>Here Section 1 students = 20
</em>
<em>
Section 2 students = 30
</em>
<em>
Here there are 15 graded exam papers.
</em>
<em>
(a )Here Pr(10 are from second section) = ²⁰C₅ * ³⁰C₁₀/⁵⁰C₁₅= 0.2070
</em>
<em>
(b) Here if x is the number of students copies of section 2 out of 15 exam papers.
</em>
<em> here the distribution is hyper-geometric one, where N = 50, K = 30 ; n = 15
</em>
<em>Then,
</em>
<em>
Pr( x ≥ 10 ; 15; 30 ; 50) = 0.3798
</em>
<em>
(c) Here we have to find that at least 10 are from the same section that means if x ≥ 10 (at least 10 from section B) or x ≤ 5 (at least 10 from section 1)
</em>
<em>
so,
</em>
<em>
Pr(at least 10 of these are from the same section) = Pr(x ≤ 5 or x ≥ 10 ; 15 ; 30 ; 50) = Pr(x ≤ 5 ; 15 ; 30 ; 50) + Pr(x ≥ 10 ; 15 ; 30 ; 50) = 0.0140 + 0.3798 = 0.3938
</em>
<em>
Note : Here the given distribution is Hyper-geometric distribution
</em>
<em>
where f(x) = kCₓ)(N-K)C(n-x)/ NCK in that way all these above values can be calculated.</em>
Answer:
Step-by-step explanation:\
my quick answer for you would be to look is there is a website on the paper so that way you can search online and see what they give you.
