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svetlana [45]
3 years ago
6

Carla use two and three cups and one and three eight how much does she use in all

Mathematics
1 answer:
alekssr [168]3 years ago
8 0
2 and 1/24 cups hope this helps
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ABC is similar to XYZ. The length of AB is 3 inches. The length of BC is 5 inches. The length of YZ is 13 inches. What is the le
Marrrta [24]

Answer:

7.8

Step-by-step explanation:

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2 years ago
Can someone please solve this for me
Savatey [412]

Answer:

m<JKD = 22 degrees

Step-by-step explanation:

21x + 5 + 4x + 2 = 132

25x + 7 = 132

25x = 125

x = 5

m<JKD = 4x + 2

4(5) + 2

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22

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2 years ago
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Hello there can anyone solve this plz (chart is attached):
stich3 [128]

Answer:

h^\prime(1)=14

Step-by-step explanation:

We have the function:

h(x)=f[f(x)]

And we want to find:

h^\prime(1)

So, we will differentiate function <em>h</em>. By the chain rule, this yields:

h^\prime(x)=f^\prime[f(x)]\cdot f^\prime(x)

Then it follows that:

h^\prime(1)=f^\prime[f(1)]\cdot f^\prime(1)

Using the table, we acquire:

h^\prime(1)=f^\prime(3)\cdot2

And using the table again, we acquire:

h^\prime(1)=7\cdot 2

Evaluate. Hence:

h^\prime(1)=14

6 0
3 years ago
Write y = 2x + 3 using function notation
Darya [45]
F(x) = 2x + 3 i think would be the best way to write it
8 0
3 years ago
a train travels 288km at a uniform speed.if the speed has been 4km per hour more it would have taken one hour less for the same
Lostsunrise [7]

Given:

A train travels 288 km at a uniform speed.

If the speed has been 4 km per hour more it would have taken one hour less for the same journey.

To find:

The initial speed of the train.

Solution:

Let x km/h be the initial speed on the train.

New speed of train = (x+4) km/h

We know that,

Time=\dfrac{Distance}{Speed}

Time taken by the train initially to cover 288 km is \dfrac{288}{x} hours.

New time taken by the train to cover 288 km is \dfrac{288}{x+4} hours.

It is given that If the speed has been 4 km per hour more it would have taken one hour less for the same journey.

\dfrac{288}{x}-\dfrac{288}{x+4}=1

\dfrac{288(x+4)-288x}{x(x+4)}=1

288x+1152-288x=x^2+4x

1152=x^2+4x

0=x^2+4x-1152

Splitting the middle term, we get

x^2+36x-32x-1152=0

x(x+36)-32(x+36)=0

(x+36)(x-32)=0

x=-36,32

We know that the speed cannot be negative. So, the only possible value of x is 32.

Therefore, the speed of the train is 32 km/h.

3 0
2 years ago
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