Factor out: 5y^2-2y-7
1 answer:
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The vertex-form equation is
y = a(x+1)² -16
Putting in the y-intercept values, we have
-15 = a(0+1)² -16
1 = a . . . . . . . . . . . add 16
Then the x-intercepts can be found where y=0.
0 = (x+1)² -16
16 = (x+1)²
±4 = x+1
x = -1 ± 4 = {-5, 3}
y = a(x+1)² -16
Putting in the y-intercept values, we have
-15 = a(0+1)² -16
1 = a . . . . . . . . . . . add 16
Then the x-intercepts can be found where y=0.
0 = (x+1)² -16
16 = (x+1)²
±4 = x+1
x = -1 ± 4 = {-5, 3}
Answer:
Step-by-step explanation:
Given the expressions all that is required is to expand them (using the distributive property) to see which answers they match up to:
For a:
For b:
For c calculate the square of a sum:
(add like terms) c:
For d: