Solve x2+12x=-11 by completing the square . Which is the the solution set of the equation?
2 answers:
Answer:
{- 11, - 1 }
Step-by-step explanation:
Since the coefficient of the x² term is 1 , to complete the square
add (half the coefficient of the x-term )² to both sides
x² + 2(6)x + 36 = - 11 + 36 ← complete the square on the left side
(x + 6)² = 25 ( take the square root of both sides
= ±
x + 6 = ± 5 ( subtract 6 from both sides )
x = - 6 ± 5
x = - 6 + 5 = - 1 or x = - 6 - 5 = - 11
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<h2>Answer:</h2>
The vertex of the function is:
(-2,-2)
<h2>Step-by-step explanation:</h2>We are given a absolute value function f(x) in terms of variable "x" as:
We know that for any absolute function of the general form:
the vertex of the function is : (h,k)
and if a<0 the graph of function opens downwards.
and if a>0 the graph of the function opens upwards.
Hence, here after comparing the equation with general form of the equation we see that:
a= -1<0 , h= -2 and k= -2
Since a is negative , hence, the graph opens down .
Hence, the vertex of the function is:
(-2,-2)