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3 years ago

-ax-20=-14 solve the equation

Mathematics

1 answer:

fiasKO [112]3 years ago

3 0

-ax-20=-14
add 20 to both sides
-ax=6

kristina

2 years ago

I dont think this is the correct answer

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What's the next number? 0 , 1/3 , 1/2 , 3/5 , 2/3

madam [21]

Answer:

The next number of the series 0, 1/3, 1/2, 3/5, and 2/3 is 5/7

Step-by-step explanation:

The given numbers are;

0, 1/3, 1/2, 3/5, and 2/3

The number sequence is formed adding $\dfrac{1}{\left (\dfrac{n^2 + n}{2} \right ) }$ to each (n - 1)th term to get the nth term number in the sequence, with the first term equal to 0, as follows;

For the 2nd term, the (n - 1)th term is 0, and n = 2, gives;

The

$0 +\dfrac{1}{\left (\dfrac{2^2 + 2}{2} \right ) } = 0 + \dfrac{1}{3} = \dfrac{1}{3}$

For the 3rd term, the (n - 1)th term is 1/3, and n = 3, gives;

$\dfrac{1}{3} +\dfrac{1}{\left (\dfrac{3^2 + 3}{2} \right ) } = \dfrac{1}{3} + \dfrac{1}{6} = \dfrac{1}{2}$

For the 4th term, the (n - 1)th term is 1/2, and n = 4, gives;

$\dfrac{1}{2} +\dfrac{1}{\left (\dfrac{4^2 + 4}{2} \right ) } = \dfrac{1}{2} + \dfrac{1}{10} = \dfrac{3}{5}$

For the 5th term, the (n - 1)th term is 3/5, and n = 5, gives;

$\dfrac{3}{5} +\dfrac{1}{\left (\dfrac{5^2 + 5}{2} \right ) } = \dfrac{3}{5} + \dfrac{1}{15} = \dfrac{2}{3}$

For the next or 6th term, the (n - 1)th term is 2/3, and n = 6, gives;

$\dfrac{2}{3} +\dfrac{1}{\left (\dfrac{6^2 + 6}{2} \right ) } = \dfrac{2}{3} + \dfrac{1}{21} = \dfrac{15}{21} = \dfrac{5}{7}$

The next number of the series 0, 1/3, 1/2, 3/5, and 2/3 = 5/7.

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