Answer:
Controller APs is the correct answer to the following question.
Explanation:
Because controller APs is the type of APs you can secure your wireless access point of the campus and any other organization. This is one of the better ways to protect or secure your AP that can be controlled by the individual device which permit the centralized management.
So, that's why the following option is correct.
Answer:
Different business or firm tend to enforce different Information Systems based completely on their main business operations, in order to best leverage data as an organizations asset. Some of these Information System are as follow:
a) Transaction Processing System
(TPS):
A small organization tends to process transactions that might result from day-to-day activities, such as purchase orders, creation of paychecks and thus require using TPS.
b) Management Information System(MIS):
Managers and owners of small organizations tend to incline towards industry-specific MIS, in order to get historical and current operational data, such as inventories data and sales.
c) Decision Support System
(DSS):
A DSS to allow managers and owners of small organizations to use predefined report in order to support problem-resolution decisions and operations planning.
He could use bold or bigger text just a suggestion.
Answer:
Total Memory= 4 KB = 4096 bytes = 32768 bits
Explanation:
<em><u>1. Data lines are 8 From D0 to D7</u></em>
so
Total memory at single address locations is 8 bits.
<em><u>2. Address lines are 12 (A0 to A11)</u></em>
There are 12 address lines but 3 out 12 are for selction of chip or memory bank.
so only 9 pins are there to address the locations on one chip.
Total No. of address locations on single chip = 2^9 = 512 locations
as 1 location is 1 byte so total memory of single chip is 512 bytes.
<u><em>3. Total Memory Bank </em></u>
There are total 3 selection pins for memory bank.
so
Total chips = 2^3 = 8.
<em><u>4. Total Memory </u></em>
Total size of 1 chip = 512 bytes
Total size of 8 chip = 8x512 bytes = 4096 bytes = 4096/1024 kb = 4 kb
<em>So total memory of system is 4 Kb = 4096 bytes = 32768 bits</em>
