Question

Use technology or a z-score table to answer the question.

Answer 1

Answer: A:60%

Step-by-step explanation:

Since the scores for a golf tournament are normally distributed, we would apply the formula for normal distribution which is expressed as

z = (x - µ)/σ

Where

x = scores for the tournament.

µ = mean score

σ = standard deviation

From the information given,

µ = 210

σ = 80

We want to find the probability percent of golfers that scored less than Ella. It is expressed as

P(x < 230)

z = (230 - 210)/80 = 0.25

Looking at the normal distribution table, the probability corresponding to the z score is 0.5987

Therefore, the percent of golfers that scored less than Ella is

0.5987 × 100 = 59.87

Approximately 60%