Year 1978 1979 1980 1990 1991 1996 1997 2007 2008 2009 Minimum hourly wage ($) 2.65 2.90 3.35 3.80 4.25 4.75 5.15 5.85 6.55 7.25
Write the least squares regression equation that models the data. Let x = time in years since 1900 and let y = minimum hourly wage. (Round your values to the nearest hundredth.) Use the equation to estimate the minimum hourly wage of a Colorado State worker in 2025. Show your work.
1 answer:
From the excel plotting, we see that the least square regression equation is given by:
m=(7.25-2.65)/(2009-1978)
m=0.15
thus the equation will be:
0.15(x-0)=y-2.65
y=0.15x-2.65
b] Using the equation we can approximate the hourly wage in 2025 as follows:
x=(2025-1978)=47
y=0.15(47)-2.65
y=7.05-2.65
y=4.4
The plot is as shown in the figure:
m=(7.25-2.65)/(2009-1978)
m=0.15
thus the equation will be:
0.15(x-0)=y-2.65
y=0.15x-2.65
b] Using the equation we can approximate the hourly wage in 2025 as follows:
x=(2025-1978)=47
y=0.15(47)-2.65
y=7.05-2.65
y=4.4
The plot is as shown in the figure:
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Answer:
Vertex: (-4, -1)
Y-intercept: (0, 15)
Step-by-step explanation:
Given the quaratic function, h(x) = x² + 8x + 15:
In order to determine the vertex of the given function, we can use the formula, .
In the quadratic function, h(x) = x² + 8x + 15, where:
a = 1, b = 8, and c = 15:
Substitute the given values for <em>a</em> and <em>b</em> into the equation to solve for the x-coordinate of the vertex.
x = -4
Subsitute the value of the x-coordinate into the given function to solve for the <u>y-coordinate of the vertex</u>:
h(x) = x² + 8x + 15
h(-4) = (-4)² + 8(-4) + 15
h(-4) = 16 - 32 + 15
h(-4) = -1
Therefore, the vertex of the given function is (-4, -1).
<h3>Solve for the Y-intercept:</h3>The <u>y-intercept</u> is the point on the graph where it crosse the y-axis. In order to find the y-intercept of the function, set x = 0, and solve for the y-intercept:
h(x) = x² + 8x + 15
h(0) = (0)² + 8(0) + 15
h(0) = 0 + 0 + 15
h(0) = 15
Therefore, the y-intercept of the quadratic function is (0, 15).