To solve this, you’ll first need to solve for their slopes.
The slope for line Q is y2-y1/x2-x1 = -8-(-2)/-8-(-10) = -3
We know that the lines are perpendicular so the negative reciprocal of -3 is 1/3
The equation you get it y = 1/3x + b.
Now you will need to solve for b by substituting in the first ordered pair of line R.
2 = 1/3(1) + b.
Once you solve for b, you should get 5/3 and y = 1/3x + 5/3
Now, to find a, you will need to substitute in 10 from the second ordered pair into x in your new equation.
y = 1/3(10) + 5/3.
Your solution should be 5.
So your answer is: a = 5
Answer:
min{5 x^2 - 20 x + 3} = -17 at x = 2
Step-by-step explanation: here's the graph
5 squared is 5^2.
Squared means the power of two, so exponent two.
Answer:
f(x)= (x+8)^2 + 200
Step-by-step explanation:
-b/2a gives you the x coordinate of the vertex and then plug it in for x to get the y coordinate. Put it in the formula (f()x= (x-h)^2 +k).
H is the x coordinate and K is the y coordinate
It would be pi over 6, 5 pi over 6, and 3 pi over 6.
