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Snezhnost [94]
3 years ago
14

A ferris wheel is 10 meters in diameter and boarded from a platform that is 5 meters above the ground. The six o'clock position

on the ferris wheel is level with the loading platform. The wheel completes 1 full revolution in 2 minutes. The function h = f(t) gives your height in meters above the ground t minutes after the wheel begins to turn. Write an equation for h = f(t).
Mathematics
1 answer:
Murrr4er [49]3 years ago
5 0

Answer:

The equation is:

f (t) = 4 + 5 (1 - cos (2pi t / 2))

Step-by-step explanation:

with the previous exercise we look for the equation for h = f (t)

So the data we have are

Wheel diameter = 10m (wheel radius = 5m)

1 wheel gets 1 revolution in 2 minutes.

the beginning of a entry will be related to that f (0) = 4

our wish is that f (z) get at least 4 with an amplitude of 5 (this value determines the radius of the wheel) for 2 minutes

with this the particle f (t) is transformed into

f (t) = 4 + 5 (1 - cos (2pi t / 2))

We know that the maximum value of cos in t will be 0, 1 -cos has minutes, the result will be as follows:

f (t) = 4 + 5 (1 - cos (2pi t / 2))

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borishaifa [10]

Answer:

12

Step-by-step explanation:

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4 0
3 years ago
Water pressure increases 0.44 pounds per square inch (0.44 psi) with each increase of one foot in depth below sea level. Identif
prohojiy [21]

Answer:

Depth below sea level is the independent quantity,

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Step-by-step explanation:

An independent quantity is a variable that can be changed in an experiment. While, dependent quantity results from the independent quantity or we can say, that depends upon the independent quantity.

Here,

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3 0
3 years ago
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3 0
3 years ago
Please show working out thanks
IgorLugansk [536]

Answer:

10m x 15m

Step-by-step explanation:

You are given some information.

1. The area of the garden: A₁ = 150m²

2. The area of the path: A₂ = 186m²

3. The width of the path: 3m

If the garden has width w and length l, the area of the garden is:

(1) A₁ = l * w

The area of the path is given by:

(2) A₂ = 3l + 3l + 3w + 3w + 4*3*3 = 6l + 6w + 36

Multiplying (2) with l gives:

(3) A₂l = 6l² + 6lw + 36l

Replacing l*w in (3) with A₁ from (1):

(4) A₂l = 6l² + 6A₁ + 36l

Combining:

(5) 6l² + (36 - A₂)l +6A₁ = 0

Simplifying:

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This equation can be factored:

(7) (l - 10)*(l - 15) = 0

Solving for l we get 2 solutions:

l₁ = 10, l₂ = 15

Using (1) to find w:

w₁ = 15, w₂ = 10

The two solutions are equivalent. The garden has dimensions 10m and 15m.

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