Y=2/x-3 make x the subject
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Let 
be the length of the rectangle and 
be the width. In the problem it is given that 
. It is also given that the area 
. Substituting in the length in terms of width, we have 
. Using the zero product property, 
. Solving these we get the width 
. However, it doesn't make sense for the width to be negative, so the width must be 
. From that we can tell the length 
.