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Dmitriy789 [7]
4 years ago
9

An element with mass 780 grams decays by 16.3% per minute. How much of the element is remaining after 16 minutes, to the nearest

10th of a gram?
Mathematics
1 answer:
rjkz [21]4 years ago
5 0

Answer:

45.3 grams will be left

Step-by-step explanation:

Use the formula

A = P(1 - r)^t     where A is the final amount, P is the initial amount, r is the percent change as a decimal, and t is the amount of time

Plug in what we know, we are given P = 780, r = 0.163, and t = 16

A = 780(1 - 0.163)^16

Now simplify...

A = 780(0.837)^16

        A = 45.25868493  

 

                  A = 45.3

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mario62 [17]
Answer: choice A) 7017

==========================================================

Work Shown:

The first term is a_1 = 24 and we go up by 7 each time.
The common difference is d = 7

The nth term formula we'll use is
a_n = a_1 + (n-1)*d
a_n = 24 + (n-1)*7

----------

The 1000th term corresponds to n = 1000

Replace every n with 1000
Then use the order of operations (PEMDAS) to simplify

a_n = 24 + (n-1)*7
a_1000 = 24 + (1000-1)*7
a_1000 = 24 + (999)*7
a_1000 = 24 + 6993
a_1000 = 7017
3 0
4 years ago
4. ADEF is an equilateral triangle.<br> E<br> 24<br> 20<br> D<br> F
irinina [24]

By Pythagorean theorem

x²+GF²=EF² ( where G is the point of intersection of perpendicular lines)

now, GF=1/2 EF= 12

x²+12²=24²

x²=24²-12²

x²=432

x=√432

x=12√3

x≈20.78

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3 years ago
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