<span>Formula: H(t) = 56t – 16t^2
</span>
H(t) = - 16t^2 + 56t
<span><span>A.
</span>What is the height of the ball after 1 second? H
(1) = 56(1) – 16(1) ^2 = 40 pt.</span>
<span><span>B.
</span>What is the maximum height? X = - (56)/2(- 16) =
1.75 sec h (1.75) = 56(1.75) – 16(1.75) ^2 h (1.75) = 49ft.</span>
<span><span>C.
</span><span>After how many seconds will it return to the
ground? – 16t^2 + 56t = 0 - 8t =0 t = 0</span></span>
<span><span>-
</span><span>8t (2 + - 7) = 0 2t – 7 = 0 t = 7/2
Ans: 3.5 seconds</span></span>
Answer: 0.000
Step-by-step explanation:
If he charges $145 he worked for 5 hours at $20 an hour
Each lap = 4.02 km
200 laps x 4.02 = 804 km total
804 km / 240 km/h = 3.35 hours = 3 hours and 21 minutes
If you mean h(4)
h(4)=(4)*2 -5(4)
=8-20
=-12
The answer will be-12