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3 years ago

What is the operation in the expression x-3?

Mathematics

2 answers:

ss7ja [257]3 years ago

7 0

Answer:

Subtraction

Step-by-step explanation:

- this sign means to take away or in other words subtract.

REY [17]3 years ago

4 0

Answer:

Step-by-step explanation:

Subtraction because there is a minus sign

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Explain why triangleABC is similar to triangle triangle ADE

DedPeter [7]

Answer:

In the given figure, line segment is constructed on the triangle parallel to line segment . ... This line can then be considered as a transversal of these parallel lines. Angle and angle are therefore corresponding angles. And as they're corresponding, this means that they're equal.

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2 years ago

Please help me please will give brainliest to

uranmaximum [27]

Answer:

<h3>step by step explanation</h3>

I hope it's help

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2 years ago

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Jlenok [28]

Answer:

$x>2$

Step-by-step explanation:

When given the following inequality;

$(x^2+x-3):(x^2-4)\geq1$

Rewrite in a fractional form so that it is easier to work with. Remember, a ratio is another way of expressing a fraction where the first term is the numerator (value over the fraction) and the second is the denominator(value under the fraction);

$\frac{x^2+x-3}{x^2-4}\geq1$

Now bring all of the terms to one side so that the other side is just a zero, use the idea of inverse operations to achieve this:

$\frac{x^2+x-3}{x^2-4}-1\geq0$

Convert the (1) to have the like denominator as the other term on the left side. Keep in mind, any term over itself is equal to (1);

$\frac{x^2+x-3}{x^2-4}-\frac{x^2-4}{x^2-4}\geq0$

Perform the operation on the other side distribute the negative sign and combine like terms;

$\frac{(x^2+x-3)-(x^2-4)}{x^2-4}\geq0\\\\\frac{x^2+x-3-x^2+4}{x^2-4}\geq0\\\\\frac{x+1}{x^2-4}\geq0$

Factor the equation so that one can find the intervales where the inequality is true;

$\frac{x+1}{(x-2)(x+2)}\geq0$

Solve to find the intervales when the equation is true. These intervales are the spaces between the zeros. The zeros of the inequality can be found using the zero product property (which states that any number times zero equals zero), these zeros are as follows;

$-1, 2, -2$

Therefore the intervales are the following, remember, the denominator cannot be zero, therefore some zeros are not included in the domain

$x\leq-2\\-2$

Substitute a value in these intervales to find out if the inequality is positive or negative, if it is positive then the interval is a solution, if it is negative then it is not a solution. This is because the inequality is greater than or equal to zero;

$x\leq-2$ -> negative

$-2$ -> neagtive

$-1\leq x$ -> neagtive

$x>2$ -> positive

Therefore, the solution to the inequality is the following;

$x>2$

6 0

2 years ago

PLEASE HELP ASAP!!!!!!!!!!!!!!!!!!!!!

maxonik [38]

The number in parenthesis after f is the x coordinate. Basically, it says which y coordinate is tied with an x value. In choice a, it says that when x is 0 y is 3, etc.

So, you can look at the graph to see which answer choice has a point from the graph. Choice a says (0,3), and that does not match. Choice b says (5,-1) and that does match. So the answer is B.

*(x,y)*

5 0

3 years ago

Read 2 more answers

What are the solutions to the equation (2x - 5) (3x - 1) = 0

SCORPION-xisa [38]

Answer:

x = 5/2 & x = 1/3

Step-by-step explanation:

Create two equations and solve

1) 2x-5 = 0 & 2) 3x-1 = 0

1) 2x = 5

x = 5/2

2) 3x = 1

x = 1/3

You create two equations as you want the left hand side (LHS) to equal 0 (RHS), thus if one of the brackets becomes 0 it will result in the whole LHS beocming 0 as the brackets are being multiplied (anything multiplied by 0 = 0)

6 0

3 years ago