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7nadin3 [17]
3 years ago
15

Convert 19'54" into a fraction of a degree. A. (199/600)° B. (199/1,200)° C. (199/900)° D. (199/1,800)°

Mathematics
2 answers:
Rufina [12.5K]3 years ago
8 0

Your answer is going to be A

inysia [295]3 years ago
6 0

The answer is A (199/600)

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In a survey of 400 randomly selected​ people, it was determined that 22 play soccer. What is the probability that a randomly sel
insens350 [35]

Answer:

5.5% probability that a randomly selected person plays​ soccer

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

Desired outcomes:

People surveyed who play soccer, so D = 22

Total outcomes:

Total people surveyed, so P = 400

What is the probability that a randomly selected person plays​ soccer?

P = \frac{D}{T} = \frac{22}{400} = 0.055

5.5% probability that a randomly selected person plays​ soccer

6 0
3 years ago
Anyone Great at math? Here you go!
Arisa [49]

the blue dotted line means the parent function was shifted 2 units down

 so the graph is g(x) = (1/3)^x-2


Answer would be A.

6 0
3 years ago
What is the area of the squares with sides (2x-3)feet?​
LUCKY_DIMON [66]

Answer:

4x^2 -12x +9   ft^2

Step-by-step explanation:

The area of a square is

A = s^2 where s is the side length

A = (2x-3) ^2

A = (2x-3) (2x-3)

FOIL

first 2x*2x =4x^2

outer 2x (-3) = -6x

inner -3*2x = -6x

last -3*-3 = 9

Add them together

4x^2 -6x-6x +9

Combine like terms

4x^2 -12x +9

The area is 4x^2 -12x +9 ft^2

5 0
3 years ago
Read 2 more answers
There is a triangle with a perimeter of 63 cm, one side of which is 21 cm. Also, one of the medians is perpendicular to one of t
NemiM [27]

Answer:

21cm; 28cm; 14cm

Step-by-step explanation:

There is no info in the problem/s  text which one of the triangle's  side is 21 cm. That is why we have to try all possible variants.

Let the triangle is ABC . Let the AK is the angle A bisector and BM is median.

Let O is AK and BM cross point.

Have a look to triangle ABM.  AO is the bisector and AOB=AOM=90 degrees (means that AO is as bisector as altitude)

=> triangle ABM is isosceles => AB=AM  (1)

1. Let AC=21   So AM=21/2=10.5 cm

So AB=10.5 cm as well.  So BC= P-AB-AC=63-21-10.5=31.5 cm

Such triangle doesn' t exist ( is impossible), because the triangle's inequality doesn't fulfill.  AB+AC>BC ( We have 21+10.5=31.5 => AB+AC=BC)

2. Let AB=21 So AM=21 and AC=42 .So  BC= P-AB-AC=63-21-42=0 cm- such triangle doesn't exist.

3. Finally let BC=21 cm. So AB+AC= 63-21=42 cm

We know (1) that AB=AM so AC=2*AB.  So AB+AC=AB+2*AB=3*AB

=>3*AB=42=> AB=14 cm => AC=2*14=28 cm.

Let check if this triangle exists ( if the triangle's inequality fulfills).

BC+AB>AC    21+14>28 - correct=> the triangle with the sides' length 21cm,14 cm, 28cm exists.

This variant is the only possible solution of the given problem.

6 0
3 years ago
6,691 ÷28<br><img src="https://tex.z-dn.net/?f=6691%20%5Cdiv%2028" id="TexFormula1" title="6691 \div 28" alt="6691 \div 28" alig
slava [35]

The question you've asked and the question on the attachment are different.

6691 ÷ 28  = 238.9642857

2409 ÷ 19 = 126.7894737

6 0
3 years ago
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