What's is the converse of the statement?If x is odd, then 2x is even.

1 answer:

dsp733 years ago

7 0

If you have two statements p and q and $p\Rightarrow q$ is true, then $\neg q\Rightarrow \neg p$ is also true.

In your case, statements are p - "x is odd" and q - "2x is even".

Then $\neg p$ - "x is not odd" and $\neg q$ - "2x is not even."

Hence $\neg q\Rightarrow \neg p$ sounds as: "If 2x is not even, then x is not odd".
Answer: correct choice is D.

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Show with work please.

kolbaska11 [484]

Answer:

$\csc \left(\theta-\frac{\pi }{2}\right)=0.73$

Step-by-step explanation:

The identity you will use is:

$\csc \left(x\right)=\frac{1}{\sin \left(x\right)}$

So,

$\csc \left(\theta-\frac{\pi }{2}\right)$

$\csc \left(\theta-\frac{\pi }{2}\right)=\frac{1}{\sin \left(-\frac{\pi }{2}+\theta\right)}$

Now, using the difference of sin

Note: state that $\text{sin}(\alpha\pm \beta)=\text{sin}(\alpha) \text{cos}(\beta) \pm \text{cos}(\alpha) \text{sin}(\beta)$

$\csc \left(\theta-\frac{\pi }{2}\right)=\frac{1}{-\cos \left(\theta\right)\sin \left(\frac{\pi }{2}\right)+\cos \left(\frac{\pi }{2}\right)\sin \left(\theta\right)}$