The temperature outside a plane flying at an altitude of 5 kilometers is -17°C.
Given that,
- The ground temperature at the airport is 10 °C.
- The decrease in temperature is 5.4°C for each & every rise in 1 kilometer.
Based on the above information, the temperature outside should be
The decrease in the temperature should be
= 5.4×5
= 27°C
Now the final temperature is
= 10 - 27
= -17°C
Therefore we can conclude that the temperature outside a plane flying at an altitude of 5 kilometers is -17°C.
Learn more: brainly.com/question/20459283
To write 4 as a time you write 4:00, Then the word after means to add 23 minutes to the 4 so we have 4:23
Answer:
x is 11
Step-by-step explanation:
We know the slope (3/4) and a point (3,-4), so we can use point-slope form (y-y1=m(x-x1)
Substitute the numbers into the equation
y--4=3/4(x-3)
simplify
y+4=3/4(x-3)
do the distributive property
y+4=3/4x-9/4
subtract 4 from both sides
y=3/4x-25/4
this is the equation of the line.
Since it says that (x,2) is a point in the equation, we can substitute it into the equation
2=3/4x-25/4
add 25/4 to both sides
33/4=3/4x
multiply by 4/3
11=x
we can double check by plugging (11,2) into the equation of the line.
2=3/4(11)-25/4
2=33/4-25/4
2=2
it works! :)
Hope this helps!
Answer:
the answer is the 2nd, 3rd, and 4th ones
Step-by-step explanation:
Answer:
Step-by-step explanation:
