A typical large orb spider has a mass of 0.50

1 answer:

3 0

The tensile strength of spider silk is about 1150 MPa, which is 1.15 x 10^9 N/m².

So given that the diameter of the spider silk is 0.15 mm or 1.5 x 10^-4 m. The cross sectional area is approximately: 

A = πr² = (3.14)(1.5 x 10^-4 / 2)² = 1.767 x 10^-8 m² 

So this means that the amount of force we can apply before the the silk thread is broken is: 

F = PA = (1.15 x 10^9)(1.767 x 10^-8) = 20.32 N 

F = mg, so m = F/g = (20.32)/(9.81) = 2.07 kg!!!

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Answer:

Luis would need to have a SAT score of 574.

Step-by-step explanation:

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Problems of normal distributions can be solved using the z-score formula.

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$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

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