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Likurg_2 [28]
2 years ago
7

A typical large orb spider has a mass of 0.50

Mathematics
1 answer:
romanna [79]2 years ago
3 0
The tensile strength of spider silk is about 1150 MPa, which is 1.15 x 10^9 N/m². 

<span>So given that the diameter of the spider silk is 0.15 mm or 1.5 x 10^-4 m. The cross sectional area is approximately: </span>

<span>A = πr² = (3.14)(1.5 x 10^-4 / 2)² = 1.767 x 10^-8 m² </span>

<span>So this means that the amount of force we can apply before the the silk thread is broken is: </span>

<span>F = PA = (1.15 x 10^9)(1.767 x 10^-8) = 20.32 N </span>

<span>F = mg, so m = F/g = (20.32)/(9.81) = 2.07 kg!!! </span>
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<u>Answer:</u>

B.    f^{-1}(x) = \frac{x + 3}{9}

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let \space\ y = f(x)\\\\y = 9x -3\\

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9x = y + 3\\\\x = \frac{y + 3}{9} \\

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Option (c) "r=\dfrac{q}{4c}-h"

Step-by-step explanation:

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q = c4(h + r)

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\dfrac{q}{4c}=\dfrac{4c}{4c}(h+r)\\\\(h+r)=\dfrac{q}{4c}

Now, subtract h both sides of the equation.

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hmmm if BC is that much, then AB + AC = 7, since AB + AC + BC = 12 which is the perimeter, Check the picture below.

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