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Ede4ka [16]
2 years ago
7

Factor the gratest common factor: -5k^2+20k-30

Mathematics
1 answer:
kumpel [21]2 years ago
6 0

Answer:

±5

Step-by-step explanation:

-5k²+20k-30

if u look at the equation ±5 are the greatest common factors so we ±5(±k²±4k±6)

You might be interested in
The total perimeter of a square is 36 inches. What is one side of the square equal to
never [62]

Note that a square has 4 congruent and equal length sides.

The total perimeter is 36

Divide 36 with 4

36/4 = 9

9 inches is your answer

hope this helps

5 0
3 years ago
The points (-1,2) and (4,y) have a slope of -4/5. what is the y-coordinate of the point (4,y)
Nastasia [14]

Answer:

y = - 2

Step-by-step explanation:

Calculate the slope m using the slope formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (- 1,2) and (x₂, y₂ ) = (4, y)

m = \frac{y-2}{4+1}, hence

\frac{y-2}{5} = - \frac{4}{5} ( cross- multiply )

5(y - 2) = - 20 ( divide both sides by 5 )

y - 2 = - 4 ( add 2 to both sides )

y = - 2

coordinates of point are (4, - 2)

7 0
3 years ago
Taliyah needs to buy 43 favors that cost 2.75 each.Estimate the total cost by rounding each number of favors to thge nearest who
nika2105 [10]

Answer: $129

Step-by-step explanation: First, you round 2.75 up to 3 and then you multiply by 43. Boom, $129.

5 0
3 years ago
Please solve this, will rate 5 stars and mark as STAR!​
Nina [5.8K]

Answer:

\boxed{5 \cdot \sqrt{2}  \cdot \sqrt[6]{5} }

Step-by-step explanation:

\sqrt[3]{250} \cdot \sqrt{\sqrt[3]{10} }

\sqrt{\sqrt[3]{10} } \implies (10^\frac{1}{3} )^\frac{1}{2} =10^\frac{1}{6} =\sqrt[6]{10}

\therefore \sqrt{\sqrt[3]{10} }=\sqrt[6]{10}

\text{Solving }\sqrt[3]{250} \cdot \sqrt{\sqrt[3]{10} }

250=2 \cdot 5^3

\sqrt[3]{250}=\sqrt[3]{2\cdot 5^3}=5  \sqrt[3]{2}

Once

\sqrt[6]{2}  \cdot \sqrt[6]{5} = \sqrt[6]{10}

We have

5  \sqrt[3]{2} \cdot \sqrt[6]{2}  \cdot \sqrt[6]{5}

We can proceed considering the common base of exponentials

\sqrt[3]{2}  \cdot \sqrt[6]{2}  =  2^{\frac{1}{3}} \cdot  2^{\frac{1}{6} }  = 2^{\frac{3}{6} } = 2^{\frac{1}{2} }=\sqrt{2}

Therefore,

5  \sqrt[3]{2} \cdot \sqrt[6]{2}  \cdot \sqrt[6]{5} = 5 \cdot \sqrt{2}  \cdot \sqrt[6]{5}

7 0
3 years ago
Someone please help me!!!
devlian [24]

Answer:

sorry cant help

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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