I have to go with True because a Rhombus is a Square.
1. Regroup terms
x^3 - 6 * 10x^2x-8/ x-3
2. Use product rule
x^3 - 6 * 10x^ 2+1 - 8/ x-3
3. Simplify
x^3 - 6 * 10 x^3 - 8/ x-3
4. Simplify further
x^3 - 60x^3 - 8/ x-3
5. Simplify the last time
-59x^3-8/x-3
, or 8.60
Just use the distance formula
Answer:

Step-by-step explanation:
<u><em>The question is</em></u>
How do you write an equation for a circle with center (-15,11) and radius 2?
we know that
The equation of a circle in center radius form is given by

where
(h,k) is the center of the circle
r is the radius of the circle
substitute the given vales


Answer:
eight and thirty-seven fiftyths
Step-by-step explanation:
6 and 4/100 + 2 and 5/10
6 and 1/25 + 2 and 1/2
156 / 25 + 5 / 2
312 / 50 + 125 / 50
437 / 50
400 / 50 = 8
8 and 37 / 50