Answer:
Step-by-step explanation:
we have given thickness of atmosphere =50 km
radius of earth =6400 km
average temperature of atmosphere=15°C
Average pressure of atmosphere= 0.20 atm
we have to calculate the volume of atmosphere
so the we have to calculate the volume of atmosphere = ( volume of earth +atmosphere) - volume of earth
volume of atmosphere =
=
The question is: If the student is known to be the girl (300 girls) what is the probability of being right handed.
We know that there are 300 girls, and that out of those 300, there are 250 girls right handed.
Divide 250 with 300
250/300 = 0.83333, or 83.33%
0.83333, or 83.33% is your answer
hope this helps
DEF= 6 ft^2
A= 1/2*b*h
Plug in what you know.
6= 1/2*4*h
Multiply like terms.
6=2*h
Divide 2 on both sides.
3=h
If the base of ABC= 12
12/4=3
3*3=9
A= 1/2*b*h
A= 1/2*12*9
A= 1/2*84
A= 42
The area of ABC is 42 ft^2
I hope this helps!
~kaikers
Ok. So first plug in the X.
8[1/8(4)] + 6(4)
Then do the work
8(1/2) + 24
4+24
28
The answer is 28
x + 4 = 3x - 8, is assuming D is the midpoint, and therefore ED = DB.
all we know is that D is <u>somewhere</u> in EB.
![\bf E\stackrel{x+4}{\rule[0.35em]{17em}{0.25pt}}D\stackrel{3x-8}{\rule[0.35em]{10em}{0.25pt}}B \\\\\\ EB=ED+DB\implies EB=(x+4)+(3x-8)\implies EB=4x-4](https://tex.z-dn.net/?f=%5Cbf%20E%5Cstackrel%7Bx%2B4%7D%7B%5Crule%5B0.35em%5D%7B17em%7D%7B0.25pt%7D%7DD%5Cstackrel%7B3x-8%7D%7B%5Crule%5B0.35em%5D%7B10em%7D%7B0.25pt%7D%7DB%0A%5C%5C%5C%5C%5C%5C%0AEB%3DED%2BDB%5Cimplies%20EB%3D%28x%2B4%29%2B%283x-8%29%5Cimplies%20EB%3D4x-4)
