47.72% people would obtain scores between 5 and 9.
For given question,
We have been given:
Mean, μ = 5
Standard Deviation, σ = 2
We are given that the distribution of score is a normal distribution.
We need to find the percentage of people who would obtain scores between 5 and 9.
We will use the formula for z-score.
= P(5 ≤ x ≤ 9)
= P()
= P(0 ≤ z ≤ 2)
= P(z ≤ 2) - P(z < 0)
= 0.9772 - 0.5
= 0.4772
= 47.72%
Therefore, 47.72% people would obtain scores between 5 and 9.
Learn more about the normal distribution here:
brainly.com/question/15103234
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Answer:
Step-by-step explanation:
tan42=32/w and tan48=39/w
w=32/tan42 and w=39/tan48
w=35.54 and w=35.12
35yd is the closest to either of the above widths.
(2x^3)(5x^4)
= (2*5)(x^3*x^4)
= 10x^7