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3 years ago

Please help me! Also please explain.

Mathematics

1 answer:

krok68 [10]3 years ago

5 0

Answer:

m=-10/7

Step-by-step explanation:

take your two points

(3,5) (4,-5)

(-5)-5/4-3

-10/7

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For an acute angle 0, the equation sin(0) = cos(6) is true. What is the value of ? Show or explain your answer

weqwewe [10]

Answer:

$\theta =84$

Step-by-step explanation:

Given

$sin(\theta) = cos(6)$

Required

Find $\thata$ $\theta$

In trigonometry:

If sin(A) = cos(B), then

$A + B = 90$

So, we have:

$\theta + 6 = 90$

Collect Like Terms

$\theta + 6 -6= 90-6$

$\theta = 90-6$

$\theta =84$

6 0

3 years ago

Determine whether the given value is a solution of the equation.

lana66690 [7]

Answer:

Is a solution

Step-by-step explanation:

Just do the division $\frac{52}{13}$

3 0

3 years ago

Read 2 more answers

For each pair of numbers, find a third whole number such that the three numbers form a pythagorean triple.

BabaBlast [244]

Answer:

Part 1) The third whole number is 44

Part 2) The third whole number is 40

Part 3) The third whole number is 25

Step-by-step explanation:

we know that

The Pythagoras theorem states that

In a right triangle

$c^{2} =a^{2} +b^{2}$

where

c is the greater length side

a and b are the legs

Case 1) we have

33,55

step a

Let

$a=33, b=55$

Find the value of c

$c^{2} =a^{2} +b^{2}$

$c^{2} =33^{2} +55^{2}$

$c^{2} =4,114$

$c =64.14$ ------> is not a whole number

step b

Let

$a=33, c=55$

Find the value of b

$b^{2} =c^{2} -a^{2}$

$b^{2} =55^{2} -33^{2}$

$b^{2} =1,936$

$b=44$

Case 2) we have

42,58

step a

Let

$a=42, b=58$

Find the value of c

$c^{2} =a^{2} +b^{2}$

$c^{2} =42^{2} +58^{2}$

$c^{2} =5,128$

$c =71.61$ ------> is not a whole number

step b

Let

$a=42, c=58$

Find the value of b

$b^{2} =c^{2} -a^{2}$

$b^{2} =58^{2} -42^{2}$

$b^{2} =1,600$

$b=40$

Case 3) we have

60,65

step a

Let

$a=60, b=65$

Find the value of c

$c^{2} =a^{2} +b^{2}$

$c^{2} =60^{2} +65^{2}$

$c^{2} =7,825$

$c =88.46$ ------> is not a whole number

step b

Let

$a=60, c=65$

Find the value of b

$b^{2} =c^{2} -a^{2}$

$b^{2} =65^{2} -60^{2}$

$b^{2} =625$

$b=25$

6 0

3 years ago

ΔHAT is similar to ΔCAN.

LenKa [72]

In similar triangles, the ratios of corresponding sides are equal.

This means

y/6=5/(4+5)

Cross multiply

y=5*6/(4+5)=30/9=10/3 (or 3 1/3)

6 0

4 years ago

Read 2 more answers

Please help me with this one.

Degger [83]

Answer:

2x^2 -x +1 = 0

Step-by-step explanation:

For roots α and β, the original equation can be factored as ...

f(x) = 2(x -α)(x -β)

If we add 1 to each of those roots, the factors become ...

g(x) = 2(x -(α+1))(x -(β+1))

This can be rearranged to be ...

g(x) = 2((x -1) -α)((x -1) -β)

That is, we can get the desired equation by replacing x with x-1, effectively shifting the function right one unit.

2(x -1)² +3(x -1) +2 = 0

2x^2 -x +1 = 0

5 0

3 years ago