2 years ago

-Help?-

Mathematics

1 answer:

likoan [24]2 years ago

3 0

Answer:

Step-by-step explanation:

https://tex.z-dn.net/?f=24x%5E%7B5%7Dy%5E%7B4%7D%5Csqrt%7B7x%5E%7B2%7Dy%7D

this is correct

You might be interested in

Plss I had to log out of my other account because Katie wouldn't let me do anything

Sonja [21]

Answer:

Step-by-step explanation:

Hm?

3 0

2 years ago

Create an equivalent expression for 13 ^−7 x 13 ^5.

Sveta_85 [38]

$13^{-7} \times 13^5=13^{-2}=\boxed{\frac{1}{13^2}}$

8 0

1 year ago

Read 2 more answers

Find the solution of the differential equation that satisfies the given initial condition.

Ann [662]

Answer:

I don’t know

Step-by-step explanation:

5 0

3 years ago

In the following image, AB is parallel to DC, and BC is a transversal intersecting both parallel lines.

professor190 [17]

Yea sir thanks buddy thanks again

6 0

2 years ago

A company with n employees publishes an internal calendar, where each day lists the employees having a birthday that day. What i

lutik1710 [3]

Answer: $1-(\frac{364}{365})^n$

Step-by-step explanation:

Binomial probability formula :-

$P(x)=^nC_xp^x(1-p)^x$ , where P(x) is the probability of getting success in x trials, n is the total number of trials and p is the probability of getting success in each trial.

We assume that the total number of days in a particular year are 365.

Then , the probability for each employee to have birthday on a certain day :

$p=\dfrac{1}{365}$

Given : The number of employee in the company = n

Then, the probability there is at least one day in a year when nobody has a birthday is given by :-

$P(x\geq1)=1-P(x$

Hence, the probability there is at least one day in a year when nobody has a birthday = $1-(\frac{364}{365})^n$

5 0

3 years ago