-3x^2-6x+2x-4
=-3x (x-2)+2 (x-2)
=(-3x+2)(x-2)
-3x+2=0
X=2/3
X-2=0
X=2
Hope it helps! !!!!
Answer:
A) between 7:40 and 7:45
Step-by-step explanation:
Given,
The maximum time taken by her to walk to school = 15 minutes,
Since, the school starts on 8:00 AM,
Also, 15 minutes before 8:00 AM = 7:45 AM,
Thus, the maximum time at which she has to leave home = 7: 45 AM,
Hence, the reasonable estimate of the time she should leave home to get to school by 8:00 is between 7:40 and 7:45.
OPTION A would be correct.
Summary of problem.
annual production = 60000 units
work hours per worker = 200*12=2400 hours
productivity = 0.15 unit / person-hour
Need to calculate the number of workers/persons employed.
Each unit requires 1 unit / 0.15 unit/person-hour
= 1/0.15 person-hours / unit
60000 unit requires 60000 units * 1/0.15 person-hours/unit
= 400000 person-hours
400000 person-hours requires 400000 person-hours /2400 hours = 166.7 persons
=>
The plant has 167 labourers (assuming perfect attendance).
Use the formula y=kx for this equation.
so considering that Y equals -24 then X and K must also equal that number
we already know that X is -4 but we dont know what K is.
so we divide -24 by -4 and get an answer of a positive 6 but the answer is not proven yet.
-4 times 6 is -24 meaning that the answer is 6
