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<h3>I'm solving it using substitution method:-</h3>
<h3>7x+2y=3 {given}</h3>
<h3>=>7x=3-2y</h3>
<h3>=>x=(3-2y)/7-------(1)</h3>
<h3>x-3y=30 {given}</h3>
<h3>=>x=30+3y</h3>
<h3>=>(3-2y)/7=30+3y {putting the value of x from eqn 1}</h3>
<h3>=>3-2y=210+21y</h3>
<h3>=>3-210=21y+2y</h3>
<h3>=>-207=23y</h3>
<h3>=>y= -207/23= -9</h3>
<h3>putting the value of y on eqn(1):-</h3>
<h3>x=(3-2y)/7</h3>
<h3>x=>(3-2(-9))/7=(3+18)/7=21/7=3</h3>
<h2>Hence, x=3, y= -9</h2>
✌️✌️❤️❤️
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Answer:
7x+14=0, 7x=-14, x= -2
Step-by-step explanation:
add like terms, then get x on one side, number on the other, then divide both sides by 7
What’s the question asking??
parallogram it has exactly 2 pairs of congruent angles
Answer:
Step-by-step explanation:
Firstly, move over the negative 3/4 fraction (don't forget to swap the operation i.e subtract to add):
Now, to add the two fractions, simply multiply the numerator and denominator by 3:
Now add this to the other fraction:
This can be simplified down by dividing both the numerator and denominator by 4:
Which now simplifies the original equation to:
Remove the y out of the fraction:
Now multiply both sides by 8:
Hope this helps!
