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ioda
3 years ago
7

Which is the better buy?. Store A $180 at 1/3 off Or Store B $110 at 10% off

Mathematics
2 answers:
daser333 [38]3 years ago
8 0

Answer:

Store B

Step-by-step explanation:

Store A the price would be about $120.60

Store B price would be about $99

To find store a price, you first find the discount, so

0.33 x 180 = 59.40

Then subtract this from the original price to know the total after the discount

180-59.40=120.60

Do the same thing with the other Store

110 x 0.10 = 11

110-11=99

Blababa [14]3 years ago
6 0

Answer: Store B

Step-by-step explanation:

180 / 3 = 60. 180 - 60= $120. Store A cost is $120.

110 * 0.9 = $99. Store B's cost is $99.

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25% = 1/4

So to get the unknown number, multiply 9 by 4:

9 × 4 = 36
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there are eight girls competing in an ice skating competition,in how many ways can they finish in first,second, and third place?
Andreas93 [3]
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5 0
3 years ago
Read 2 more answers
Write the factors for each number Then decide whether the number is prime or composite
Lina20 [59]

Answer:

Step-by-step explanation:

If it have more than 2 divider its composite but its divider is only one and its self only its prime.1 isn't neither prime nor composite

8 0
3 years ago
I will give brainiest to whoever answers correctly !!
Andreyy89
Answer:
Step-by-step explanation:
We would apply the simple interest formula which is expressed as
I = PRT/100
Where
P = principal or amount borrowed
T = time in years
R = interest rate on amount borrowed.
I = interest paid.
From the given information,
Principal = $3000
T = 3 months = 3/12 = 0.25 years
R = 6 1/2 % = 6.5%
Therefore,
a) the amount that the woman pay for the use of the money is I
I = (3000 × 6.5 × 0.25)/100 = 48.75
b) The amount she repaid to the bank on the due date of the note would be
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= 3000 + 48.75 = $3048.75
4 0
3 years ago
Read 2 more answers
Simplify the complex fraction.
lilavasa [31]

Given:

$\frac{\left(\frac{(4 r)^{3}}{15 t^{4}}\right)}{\left(\frac{16 r}{(3 t)^{2}}\right)}

To find:

The simplified fraction.

Solution:

Step 1: Simplify the numerator

$\frac{(4 r)^{3}}{15 t^{4}}=\frac{4^3 r^{3}}{15 t^{4}}=\frac{64 r^{3}}{15 t^{4}}

Step 2: Simplify the denominator

$\frac{16 r}{(3 t)^{2}}=\frac{16 r}{3^2 t^{2}}= \frac{16 r}{9 t^{2}}

Step 3: Using step 1 and step 2

$\frac{\left(\frac{(4 r)^{3}}{15 t^{4}}\right)}{\left(\frac{16 r}{(3 t)^{2}}\right)}=\frac{\left(\frac{64 r^{3}}{15 t^{4}}\right)}{\left(\frac{16 r}{9 t^{2}} \right)}

Step 4: Using fraction rule:

$\frac{\frac{a}{b}}{\frac{c}{d}}=\frac{a \cdot d}{b \cdot c}

$\frac{\left(\frac{64 r^{3}}{15 t^{4}}\right)}{\left(\frac{16 r}{9 t^{2}}\right)}=\frac{64r^3 \cdot 9t^2}{16 r \cdot 15 t^4}

Cancel the common factor r and t², we get

           $=\frac{64 r^{2} \cdot 9 }{16  \cdot 15 t^2 }

Cancel the common factors 16 and 3 on both numerator and denominator.

           $=\frac{4 r^{2} \cdot 3 }{  5 t^2 }

           $=\frac{12 r^{2}  }{  5 t^2 }

$\frac{\left(\frac{(4 r)^{3}}{15 t^{4}}\right)}{\left(\frac{16 r}{(3 t)^{2}}\right)}=\frac{12 r^{2}  }{  5 t^2 }

The simplified fraction is \frac{12 r^{2}  }{  5 t^2 }.

5 0
3 years ago
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