Solve for b:
b² = 8b + 84
1 answer:
B² = 8b + 84 b² - 8b - 84 = 0 b = <u>-(-8) +/- √((8)² - 4(1)(-84))</u> 2(1)<u> </u>b = <u>8 +/- √(64 + 336)</u> 2 b = <u>8 +/- √(400) </u> 2<u> </u>b = <u>8 +/- 20 </u> 2 b = 4 <u>+</u> 10 b = 4 + 10 b = 4 - 10 b = 14 b = -6 <u />
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Answer:
43,45
Step-by-step explanation:
43+45=88
A=Lw
P=2L+2w
216=Lw
W=216/L...substitute to Perimeter equation
60=2L+2(216/L)
60L=2L^2 + 432
2L^2-60L+432=0
2(L^2 - 30L + 216)=0
2(L-18)(L-12)=0
L=12, W=18 or L=18, W=12
First, you have to solve t(x) when x=4, because the crew is working 4 scripts. Which is t(x)=4+6 t(x)=10 Then, you plug in t(x) to c(x). c(x)=2(10)+4 c(x)=24
Equivalent fraction for four this is 8/10
In 2^3 the number 2 is the base of it