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3 years ago

Help me solve this please I need help

Mathematics

2 answers:

djyliett [7]3 years ago

4 0

SSS means that the appropriate sides are congruent. Since two of the sides are already given as congruent the missing sides must be congruent to demonstrate SSS. So the answer is B, GS is congruent to TD.

blondinia [14]3 years ago

3 0

GS =~ TD is the answer you want I believe

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Sliva [168]

Answer:

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Step-by-step explanation:

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3 years ago

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3 years ago

Write the rule for the nth term of the following sequence.

denis-greek [22]

Answer:

$2^{n-3}$ is the nth term of the given sequence.

Step-by-step explanation:

The sequence given is

$\frac{1}{4},\frac{1}{2},1,2,4 .....$

We can clearly see that 1st term is $\frac{1}{4}$ and 2nd term is $\frac{1}{2}$

2nd term is obtained by multiplying the 1st term by 2.

2nd term is $\frac{1}{2}$ and 3rd term is 1.

3rd term is obtained by multiplying the 2nd term by 2.

3rd term is 1 and 4th term is 2.

4th term is obtained by multiplying the 3rd term by 2.

Clearly, the given series is a Geometric Progression(GP) with

First term, $a = \frac{1}{4}$

Common Ratio, $r = 2$

We know that $n^{th}$ term for a GP is:

$a_n = ar^{n-1}$

Putting values of a and r

$a_n = \dfrac{1}{4}2^{n-1}\\a_n = \dfrac{1}{2^{2} }2^{n-1}\\a_n = 2^{n-1-2}\\a_n = 2^{n-3}$

Hence, $2^{n-3}$ is the nth term of the given sequence.

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3 years ago