Question

Solve the system algebraically. 3x - 2y - 1 = 0 y = 5x + 4 What is the solution?

Answer 1

3x - 2 ( 5x + 4 ) - 1 = 0
3x - 10x - 8 - 1 = 0
7x = - 9
x = - 9/7

y = 5 ( - 9/7 ) + 4
y = - 45/7 + 4
y = - 3/45/7

Answer 2

Answer:

$x=\frac{-9}{7}$

$y=\frac{-17}{7}$

Step-by-step explanation:

We have been given the equation:

$3x-2y-1=0$

And $y=5x+4$

Second equation can be rewritten as:

$5x-y=-4$

We will solve the equations:

$3x-2y=1$      (1)

$5x-y=-4$       (2)

Multiply equation (1) by 5 and equation (2) by 3 we get:

$15x-10y=5$      (3)

$15x-3y=-12$       (4)

Now, subtract (4) from (3) we get:

$-7y=17$

$y=\frac{-17}{7}$

Now substitute $y=\frac{-17}{7}$ in equation (1) we get:

$3x-2{\frac{-17}{7}}=1$

$3x+\frac{34}{7}=1$

$21x=-27$

$x=\frac[-27}{21}$

$x=\frac{-9}{7}$