Question

If the , points on the graphs are (-4,1) and (2,1) what is the equation ?

Answer 1

Slope-intercept form:

y = mx + b

"m" is the slope, "b" is the y-intercept

To find "m", you can use the slope formula and plug in the two points:

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

$m=\frac{1-1}{2-(-4)}$

$m=\frac{1-1}{2+4}$

$m=\frac{0}{6}=0$

The slope is 0 so:

y = mx + b

y = 0x + b     [any number multiplied by 0 is 0]

y = b      

To find "b", you plug in either of the points into the equation (since both of their y values are 1]

y = b

1 = b

Your equation is:

y = 1      (This is a horizontal line)

Answer 2

Answer:

$y=0x+1$, or $y=1$

Step-by-step explanation:

The equation will be in slope intercept form. $y=mx+b$

I can find the slope using the formula:

$\frac{y_2-y_1}{x_2-x_1}$

When I plug in: $\frac{1-1}{2-(-4)}$, I find that the slope is 0.

I can then lug in what I know into $y=mx+b$:

Using (2, 1):

1=0(2)+b. Solving for be I get: b=1

You then get your answer after you plug back in.

Hope this helps!!