Find the distance between points M (6,16) and Z (-1,14) to the nearest tenth, please help step by step

1 answer:

3 0

The distance between 2 points P(a, b) and Q(c,d) is given by the formula:

$\displaystyle{d= \sqrt{(b-d)^2+(a-c)^2}$ ,

Apply the formula for the points M(6, 16) and Z(-1, 14):

$\displaystyle{d= \sqrt{(16-14)^2+(6-(-1))^2}= \sqrt{2^2+7^2}= \sqrt{4+49}= \sqrt{53}\approx 7.28$

which rounded to the nearest tenth is 7.3 (units)

Answer: 7.3 units

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