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Vlad1618 [11]
3 years ago
14

What is the length of AC

Mathematics
1 answer:
KIM [24]3 years ago
8 0

Answer:

x=9 ⇒AC=24

Step-by-step explanation:

vì DE//B C⇒ΔABC  Tương ung ti tỉ lệ vớiv  ΔADE

⇒DB/AB=EC/AC

⇒AC=(EC.AB)/DB

⇒AC=24

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4(x-5)+5y is your answer

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Find the area bounded by y=ln x, x=2, x=4 and the x-axis.​
Advocard [28]

4 sq.units

area of a rectangle = length × breadth

length = 4units

breadth = 1units

A = l × b

= 4 × 1

= 4 sq.units

<h3><em>HOPE</em><em> </em><em>IT</em><em> </em><em>HELPS</em><em> </em><em>U</em><em> </em></h3>

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8 0
3 years ago
Which statement describes the value of the expression 4 * 18932 + 921
IceJOKER [234]
I'm confused, there are no statement. 
But <span>4 * 18932 + 921 is equal to 76,649.

4*18932+921
75728+921= 76649
</span>
8 0
3 years ago
Charles will babysit for up to 4 hours and charges $7 per hour. Write a function in function notation for this situation.
I am Lyosha [343]
Assume Charles charges $7*3=$21 if he babysits for 2,5 hours (that is 2 and a half hours).

That is we are not considering Charles babysitting exactly 1, 2, 3 or 4 hours, but also in between times.


then we can write the following piecewise function to describe the situation:


f is a function from (0, 4] to {$7, $14, $21, $28}

f(x)=\begin{cases} &#10;      \$7 & if \enspace \enspace x\leq 1 \\&#10;      \$14 & if \enspace \enspace 1\ \textless \  x\leq 2 \\&#10;      \$21 & if \enspace\enspace 2\ \textless \ x\leq 3 \\&#10;      \$28 & if \enspace\enspace 3\ \textless \ x\leq 4 \&#10;   \end{cases}
6 0
3 years ago
2 cars c and d started to move to each other car c was 118 miles from Boston car d was 256 miles from Boston car c was going twi
Vadim26 [7]

Answer:

131.3 miles

Step-by-step explanation:

The two cars are moving from different directions. The total distance between the two cars = 118 miles + 256 miles = 374 miles.

Let us assume that the two cars meet at point O, let the distance between car c and O be d₁, the distance between car d and point O be d₂, hence:

d₁ + d₂ = 374 miles       (1)

Let speed of car d be x mph, therefore speed of car c = 2x mph (twice of car d). If it take the cars t hours to meet at the same point, hence

For car c:

2x = d₁/t

t = d₁ / 2x

For car d;

x = d₂/t

t = d₂/ x

Since it takes both cars the same time to meet at the same point, therefore:

d₁/2x = d₂ / x

d₁ = 2d₂

d₁ - 2d₂ = 0         (2)

Solving equation 1 and 2 simultaneously gives d₁ = 249.3 miles, d₂ = 124.7 miles

Therefore the distance from point of meet to Boston = 249.3 - 118 = 131.3 miles

7 0
3 years ago
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