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Romashka [77]
3 years ago
13

Compete the equatuon descibing how x and y are related

Mathematics
1 answer:
Minchanka [31]3 years ago
4 0
I honestly don’t even know how to explain this- but ik that 3 should be alright to type in bc if you were to write it on a graph you would move 1 unit to the right and 3 units up from there based on the coordinates after the origin (0,0).
You might be interested in
Let M be the set of all nxn matrices. Define a relation on won M by A B there exists an invertible matrix P such that A = P BP S
Sophie [7]

Answer:

Recall that a relation is an <em>equivalence relation</em> if and only if is symmetric, reflexive and transitive. In order to simplify the notation we will use A↔B when A is in relation with B.

<em>Reflexive: </em>We need to prove that A↔A. Let us write J for the identity matrix and recall that J is invertible. Notice that A=J^{-1}AJ. Thus, A↔A.

<em>Symmetric</em>: We need to prove that A↔B implies B↔A. As A↔B there exists an invertible matrix P such that A=P^{-1}BP. In this equality we can perform a right multiplication by P^{-1} and obtain AP^{-1} =P^{-1}B. Then, in the obtained equality we perform a left multiplication by P and get PAP^{-1} =B. If we write Q=P^{-1} and Q^{-1} = P we have B = Q^{-1}AQ. Thus, B↔A.

<em>Transitive</em>: We need to prove that A↔B and B↔C implies A↔C. From the fact A↔B we have A=P^{-1}BP and from B↔C we have B=Q^{-1}CQ. Now, if we substitute the last equality into the first one we get

A=P^{-1}Q^{-1}CQP = (P^{-1}Q^{-1})C(QP).

Recall that if P and Q are invertible, then QP is invertible and (QP)^{-1}=P^{-1}Q^{-1}. So, if we denote R=QP we obtained that

A=R^{-1}CR. Hence, A↔C.

Therefore, the relation is an <em>equivalence relation</em>.

4 0
3 years ago
-2 divided by 1/4 please show your work
Aneli [31]
-2 / 1/4
If you are dividing you have to switch 1/4 to 4/1

-2/1  / 4/1
= -8
Hope this helped
6 0
3 years ago
Input output please
dlinn [17]

Step-by-step explanation:

  1. 89
  2. 81
  3. 50
  4. 83
  5. 295

<h2>hope it helps.</h2><h2>stay safe healthy and happy.</h2>
8 0
2 years ago
How could you find 3/8% of 800
Damm [24]
Well 3/8 is .375 but times 100 is 37.5%
Then 37.5% of 800 is 300
7 0
3 years ago
Read 2 more answers
Please help last question and u get 15 points
makvit [3.9K]

81.4% ≅ 81%. The probability that a customer ordered a hot drink given that he or she ordered a large is 81%.

The key to solve this problem is using the conditional probablity equation P(A|B) = P(A∩B)/P(B). Conditional probability is the probability of one event occurring with some relationship to one or more other events.

Similarly to the previous exercise, P(A∩B) is the probability that a customer order a large hot drink. So, P(A∩B) = 22/100 = 0.22

For P(B), is the probability that a customer order a large drink whether hot or cold. P(B) = 27/100 = 0.27

P(A|B) = 0.22/0.27 = 0.814

multiplying by 100%, we obtain 81.4%

8 0
3 years ago
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