Compete the equatuon descibing how x and y are related

Mathematics

1 answer:

Minchanka [31]3 years ago

4 0

I honestly don’t even know how to explain this- but ik that 3 should be alright to type in bc if you were to write it on a graph you would move 1 unit to the right and 3 units up from there based on the coordinates after the origin (0,0).

You might be interested in

I have been stuck on the problem for so long. please help me:

Xelga [282]

Answer:

D-2

Step-by-step explanation:

You can use elimination to get the value of y. Move numbers to one side and x and ys to the other side. To use elimination, multiply the first equation with 2. You will get 2x+2y=24. add it with the equation below. y will be eliminated and you will get the value of x. X=10. Plug in x and get the y value. Y=2

6 0

2 years ago

Solve 3x2 + 4x = −5.

Alla [95]

Move the -5 over by adding 5 to both sides
3x^2+4x+5=0
must use quadratic formula

for an equation in the form
ax^2+bx+c=0
x= $\frac{-b+/- \sqrt{b^2-4ac} }{2a}$

a=3
b=4
c=5

x= $\frac{-4+/- \sqrt{4^2-4(3)(5)} }{2(3)}$
x= $\frac{-4+/- \sqrt{16-60} }{6}$
x= $\frac{-4+/- \sqrt{-44} }{6}$
x= $\frac{-4+/- 2\sqrt{-11} }{6}$
remember that√-1=i
x= $\frac{-4+/- 2i\sqrt{-11} }{6}$
x= $\frac{-2+/- i\sqrt{-11} }{3}$

x= $\frac{-2+ i\sqrt{-11} }{3}$ or x= $\frac{-2- i\sqrt{-11} }{3}$

4 0

2 years ago

Find the missing side length of the right triangle 5in 15in

kumpel [21]

Answer:

15, because the sides are congruent except for the bottom ones

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Rachel recorded the number of calls she made at work during the week:

Dmitry [639]

The chi-squared test statistic will be 3.11. The test statistic is contrasted with a predicted value based on the Chi-square distribution.

<h3>What is the chi-squared test statistic?</h3>

Finding the squared difference between the actual and anticipated data values, then dividing that difference by the expected data values, constitutes the test statistic.

The formula for the chi-squared test statistic is;

$\sum \frac{(O_i-E_i)^2}{E_i } \\\\$

Where,

$\rm O_i$ is the observed value

$\rm E_i$ is the expected value

The chi-square test statics is;

$\rm( \frac{18-18}{18} )^2 +( \frac{14-18}{18} )^2 + (\frac{24-18}{18} )^2+( \frac{16-18}{18} )^2 \\\\ 0+ \frac{16}{18}+ \frac{36}{18} +\frac{4}{18}\\\\ \frac{56}{18} \\\\ 3.11$