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Sholpan [36]
2 years ago
10

Siri, who is not yet 22 years old, is five years older than Lily. Write and solve an

Mathematics
1 answer:
Zolol [24]2 years ago
8 0

Answer:

22-5= L

L = 17

Step-by-step explanation:

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NO LINKS!!!!
DedPeter [7]

9514 1404 393

Answer:

  3. vertical stretch by a factor of 2; shift right 1 and down 1

  4. shift left 4 and up 4 (no stretch or shrink)

Step-by-step explanation:

The vertex form equation is ...

  y = a(x -h)^2 +k

It represents a vertical stretch of the parent function by a factor of 'a', a right shift of 'h', and an upward shift of 'k'.

Compare the the given equations to the above form to see the transformations.

__

3. (a, h, k) = (2, 1, -1)   ⇒   vertical stretch by a factor of 2; shift right 1, down 1

4. (a, h, k) = (1, -4, 4)   ⇒   no vertical stretch; shift left 4, up 4

6 0
3 years ago
Solve the Absolute Value Equation. <br><br> |9x+1| = 46
Sedaia [141]
X = 5 (you can set it up as a regular equation)
9x + 1= 46
9x = 45 (subtracted 1 from both sides)
x = 5 (divided 45 by 9)
hope this helps :)
5 0
3 years ago
18-2x=4x drag AND drop the reasons into the boxes to correctly complete the table.
scoundrel [369]
18-2x=4x is given
18=6x is addition property of equality
3=x is I think division property of equality bc you divided to get x=3
4 0
3 years ago
Simplify (4x– 4)– 3<br><br><br> A. -1/2x^4<br><br> B. -8x^12<br><br> C. -64x^9<br><br> D. x^12/64
marysya [2.9K]
Use:(a\cdot b)^n=a^n\cdot b^n\\\\(a^n)^m=a^{n\cdot m}\\\\a^{-n}=\dfrac{1}{a^n}\\\\\left(4x^{-4}\right)^{-3}=4^{-3}(x^{-4})^{-3}=\dfrac{1}{4^3}x^{-4\cdot(-3)}\\\\=\dfrac{1}{64}x^{12}=\boxed{\frac{x^{12}}{64}}

Answer: D. x^12/64
3 0
3 years ago
Read 2 more answers
39. Rewrite each expression as an equivalent expression containing only one logarithm.
monitta

Answer:

ln{\frac{(p+q)^3}{q^2p^7} }

Step-by-step explanation:

3 ln(p + q) − 2 ln(q) − 7 ln(p)

=ln(p+q)^3- ln(q)^2-ln(p)^7

= ln(p+q)^3-{ln(q)^2+ln(p)^7}

=ln(p+q)^3-ln(q)^2*(p)^7

=ln{ (p+q)^3÷(q)^2*(p)^7}

=ln{\frac{(p+q)^3}{q^2p^7} }

3 0
3 years ago
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