Answer:
particulate hypothesis of inheritance
Explanation:
This states that the inheritable factors retain their identity generation after generation.
Microorganisms in their digestive tracts hydrolyze the cellulose to individual glucose units.
Cellulose- The stable formation of plant cell walls is greatly aided by cellulose, a hard, fibrous, and water-insoluble polysaccharide. The fibrils (bundles of microfibrils) and microfibrils (bundles of polysaccharide) made up of cellulose chains make up the plant cell wall.
Glucose- The primary form of sugar in the blood, glucose serves as the body's cells' principal source of energy. Glucose may be produced by the body from other chemicals or it can be obtained from the meals we eat. The circulation carries glucose to the cells. Insulin is one of many hormones that regulate blood glucose levels.
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Answer:
Hydrolysis
Explanation:
Hydrolysis is a reaction that needs water to breakdown macromolecules into simpler units.
Macromolecules are giant polymers made up of several repeating monomeric units.
- These units are too complex for the body to digest and derive nutritional benefits from them.
- During hydrolysis, the complex is broken down into monomers.
- The monomeric units are absorbable and useful for the body.
When a BB male and a Bb female are crossed, 50% BB and 50% Bb genotypes are produced and a 100% black phenotype.
The entire number of genes that an organism receives from its parents makes up its genotype. Alleles, which are pairs of these genes, are found. One gene is dominant and one gene is recessive in each allele.
The dominant gene is always expressed in a cross if it is present. Only when a pair of alleles is made up of two recessive genes does the recessive gene express itself. In this instance, the white fur is subordinate to the black fur. White fur is represented as b, while black fur is represented as B.
We can see that when we cross the BB male and Bb female, we will get a genotype that is 50% BB and 50% Bb, as well as a phenotype that is 100% black fur.
Parents: BB x Bb
Gametes: B, B, and B, b
Offspring: BB, BB, Bb, Bb
The genotypic ratio = 1:1
The phenotypic ratio = 1:0
Genotype probabilities:
P(BB) = 2/4 = 0.5 or 50%
P(Bb) = 2/4 = 0.5 or 50%
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