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Nesterboy [21]
3 years ago
14

Think about a density curve that consists of two straight-line segments. The first goes from the point (0, 1) to the point (0.7,

1) then the second goes from the point (0.7, 1) to the point (1.3, 0).
a. Sketch this density curve:
b. What is the probability that X falls below 0.5?
c. What is the probability that X lies between 0.7 and 1.3?
d. What is the probability that X lies above 0.2?
e. What is the probability that X is equal to 0.5?

Mathematics
1 answer:
lianna [129]3 years ago
4 0

Answer:

b)0.5

c)0.3

d)0.2

e)0.5

Step-by-step explanation:

As we see on the graph, the probability that X falls below 0.5 is 0.5.

the probability that X falls between 0.7 is 1.3 is 0.3. If the line go from the point (0.7,1) to the point (1.3, 1) the probability of X would be 0.6 that is the distance between the two points, but instead is the half because it goes from the point (0.7,1) to the point (1.3, 0).

The probability that X lies above 0.2 is 0.2 and also the probability to X is equal to 0.5 it's also 0.5

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The answer is -\frac{1}{2}

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Then you subtract the fractions.

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Finally, you need to simplify the answer.

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3 years ago
A bank manager has developed a new system to reduce the time customers spend waiting for teller service during peak hours. The m
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Answer:

(a) <em>H₀</em>: <em>μ</em> = 10 vs. <em>Hₐ</em>: <em>μ</em> < 10.

(b) The level of significance is 0.05.

Step-by-step explanation:

A new system is used to reduce the time customers spend waiting for teller service during peak hours at a bank.

A single mean test can be used to determine whether the waiting time has reduced.

(a)

The hypothesis to test whether the new system is effective or not is:

<em>H₀</em>: The mean waiting time is 10 minutes, i.e. <em>μ</em> = 10.

<em>Hₐ</em>: The mean waiting time is less than 10 minutes, i.e. <em>μ</em> < 10.

(b)

The information provided is:

\bar x=9.5\\s=2.2\\n=70

Compute the test statistic value as follows:

t=\frac{\bar x-\mu}{s/\sqrt{n}}=\frac{9.5-10}{2.2/\sqrt{70}}=-1.902

The test statistic value is <em>t</em> = -1.902.

Compute the <em>p</em>-value of the test as follows:

p-value=P(t_{n-1}

               =P(t_{69}1.902)\\=0.031

The null hypothesis will be rejected if the <em>p</em>-value of the test is less than the significance level (<em>α</em>).

The <em>p</em>-value obtained is 0.031.

To reject the null hypothesis the value of <em>α</em> should be more than 0.031.

The most commonly used values of <em>α</em> are: 0.01, 0.05 and 0.10.

So, the least value of <em>α</em> at which we can conclude that the wait times have decreased is, <em>α</em> = 0.05.

Thus, the level of significance is 0.05.

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Answer:

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