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3 years ago

PLEASE HELP ∆ARE ≌ ∆_ by _

Mathematics

1 answer:

laila [671]3 years ago

5 0

Answer:

We have:

AE ≅ AC
RE ≅ RC
AR ≅ AR

The conclusion is:

ΔARE ≅ ARC by Side-side-side (SSS) postulate

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Which equation demonstrates the distributive property?

Art [367]

The correct option of your question is D

Step-by-step explanation:

To solve the sum we need to understand the distributive property

a×(b+c) = a×b + a×c

Here,

Option D is given as

RHS = 5(3+8) [ a=5, b=3 and c=8]

=15 + 40

= LHS

It satisfies the distributive property.

You can cross check the property with the other options.

D is the correct option.

6 0

3 years ago

Read 2 more answers

Pls help ill mark brainliest!:) thank you<3

murzikaleks [220]

Answer:

(-26, 32)

Step-by-step explanation:

6 0

3 years ago

Need help with 17 pre college

Ratling [72]

No because if you plug in 4 for x and 5 for y you get -4 not 36

6 0

3 years ago

Find the slope-intercept form of the equation of the line that passes through the point (5,1) and is perpendicular to the line 2

Vlad1618 [11]

The slope-intercept form:

$y=mx+b$

m - slope

b - y-intercept

Convert 2x + 5y = 10 to the slope0intercept form:

$2x+5y=10$ subtract 2x from both sides

$5y=-2x+10$ divide both sides by 5

$y=-\dfrac{2}{5}x+2$

Let $k:y=m_1x+b_1$ and $l:y=m_2x+b_2$

$l\ \perp\ k\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}$

We have $m_1=-\dfrac{2}{5}$

Therefore

$m_2=-\dfrac{-\frac{2}{5}}=\dfac{5}{2}$

We have the equation of a line:

$y=\dfrac{5}{2}x+b$

Put the coordinates of the point (5, 1) to the equation of a line:

$1=\dfrac{5}{2}(5)+b$

$1=\dfrac{25}{2}+b$ subtract $\dfrac{25}{2}$ from both sides

$-\dfrac{23}{2}=b\to b=\dfrac{23}{2}$

Answer: $\boxed{y=\dfrac{5}{2}x+\dfrac{23}{2}}$

4 0

3 years ago

Plz tell me answer and explain how I could get the answer.

Vinil7 [7]

Answer: 349.5 miles

Step-by-step explanation:

Use the formula distance (d) = rate (r) x time (t):

Since there are two different rates and times so solve each one separately and then add them together.

$\large{d_1=r_1\times t_1\quad \rightarrow \quad r=75\ mph, t=150\ minutes}\\\\d_1=\dfrac{75\ miles}{1\ hour}\times \dfrac{1\ hour}{60\ minutes}\times 150\ minutes\\\\d_1=187.5\ miles\\\\\\\large{d_2=r_2\times t_2\quad \rightarrow \quad r=81\ mph, t=2\ hours}\\\\d_2=\dfrac{81\ miles}{1\ hour}\times 2\ hours\\\\d_2=162\ miles\\\\\\\large{\text{Total miles driven = }d_1+d_2}\\\\187.5\ miles +162\ miles = \boxed{349.5\ miles}$

7 0

3 years ago