The firs term
A(1)=-6+(1-1)(6)
A(1)=-6+(0)(6)
A(1)=-6
The fourh term
A(n)=-6+(n-1)(6)
A(4)=-6+(4-1)(6)
A(4)=-6+(3)(6)
A(4)=-6+18
A(4)=12
The tenth term
A(10)=-6+(10-1)(6)
A(10)=-6+(9)(6)
A(10)=-6+54
A(10)=48
Answer:
D. -6,12,48
0 6 77383 usuesj 727262829 -3 -3 -6 66
Because SUR=32, then RS must be 32 and because STR=64. You could also tell this because the shape in the circle is not perfectly symmetrical
Answer:
0.64
Step-by-step explanation:
P(J / R) = P (J and R) / P(R)
0.8 = P (J and R) / 0.6
P (J and R) = 0.6 * 0.8 = 0.48 [Probability John practicing and it is raining]
P(J / NR) = P (J and NR) / P(NR)
0.4 = P (J and NR) / (1 - 0.6) = P (J and NR) / 0.4
P (J and NR) = 0.4 * 0.4 = 0.16 [Probability John practicing and it is not raining]
Hence;
Probability of John practicing regardless of weather condition is
P(John Practicing) = 0.48 + 0.16 = 0.64
HOPE THIS HELPED!!!
442 is the answer thedjfbbxhcbdhx
