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3 years ago

What are the next three terms in this arithmetic sequence? 33, 27, 21,...

Mathematics

2 answers:

sladkih [1.3K]3 years ago

6 0

Answer:

15,9,3

Step-by-step explanation:

Mkey [24]3 years ago

6 0

15,9,3 is your answer

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Which are the coordinates of the x-intercept in the equation −4+5=20

Strike441 [17]

I need more information.

7 0

4 years ago

Laura wrote and solved the following expression to find the total number of beads Lina has if there are 6 beads in each packet.

bulgar [2K]

<h3>The number of beads lina has is 31</h3><h3>Laura made a mistake by adding the constant 7 and variable 4b</h3>

<em><u>Solution:</u></em>

Given that,

Laura wrote and solved the following expression to find the total number of beads Lina has

There are 6 beads in each packet

7+4b = 11b

= 11(6)

=66

From given,

Lina has a total of 7 + 4b beads

Given that, There are 6 beads in each packet

Substitute b = 6

7 + 4(6)

Simplify

7 + 24

Add

Thus, she has a total of 31 beads and not 66 beads

Laura made a mistake by adding the constant 7 and variable 4b

But a constant and variable cannot be added

4 0

4 years ago

5) (5x2 + 4) — (5 + 5x3)

Licemer1 [7]

(5x²+4)–(5+5x³)
25x+4–5+125x
150x–1

8 0

3 years ago

234 is 45% of what amount

GaryK [48]

Answer:

520?

Step-by-step explanation:

I think

3 0

3 years ago

Let the region R be the area enclosed by the function f(x)=ln(x) and g(x)= 1/2x-2. Find the volume of the solid generated when t

Neporo4naja [7]

Answer:

$V=61.66$

Step-by-step explanation:

This problem can be solved by using the expression for the Volume of a solid with the washer method

$V=\pi \int \limit_a^b[R(x)^2-r(x)^2]dx$

where R and r are the functions f and g respectively (f for the upper bound of the region and r for the lower bound).

Before we have to compute the limits of the integral. We can do that by taking f=g, that is

$f(x)=g(x)\\ln(x)=\frac{1}{2}x-2$

there are two point of intersection (that have been calculated with a software program as Wolfram alpha, because there is no way to solve analiticaly)

x1=0.14

x2=8.21

and because the revolution is around y=-5 we have

$R=ln(x)-(-5)\\r=\frac{1}{2}x-2-(-5)\\$

and by replacing in the integral we have

$V=\pi \int \limit_{x1}^{x2}[(lnx+5)^2-(\frac{1}{2}x+3)^2]dx\\$

$V=\pi [28x+\frac{1}{x}+xln^2x-12xlnx-6lnx]$

and by evaluating in the limits we have

$V=61.66$

Hope this helps

regards

3 0

3 years ago