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3 years ago

Enter numbers into the table so that the paired values are in a proportional relationship.

Mathematics

2 answers:

Alisiya [41]3 years ago

8 0

Answer:

x- 5

y- 6

Step-by-step explanation:

A proportional relationship is a relationship for which a proportional constant y/x exists and for which it passes through (0,0) or the origin.

The proportional constant is 6.

18/3=6

42/7=7

54/9=6

Thus the filled in blanks should be x 1, 3, 5, 7, 9 and y 6, 18, 30, 42, 54.

Fantom [35]3 years ago

6 0

Answer:

<h2>The missing numbers are 5 and 6.</h2>

Step-by-step explanation:

From the given table, if we divide each pair as y/x, we find the ratio is 6.

$\frac{18}{3}=6\\\frac{42}{7}=6\\\frac{54}{9}=6$

Therefore, the missing numbers have to be in the same ratio.

$\frac{x}{1}=6\\x=6$

$\frac{30}{x}=6\\ x=5$

So, the missing numbers are 5 and 6, because they are also in the same ratio of 6.

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nignag [31]

Given:

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Solution:

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3 years ago

Joe is building a post for his mailbox. To find the correct dimensions, he needs to expand this expression: (x-3) (x-9) (x-4) Se

kolbaska11 [484]

Answer:

$(x-3)(x-9)(x-4)=x^3-16x^2+75x-108$

Step-by-step explanation:

Given:

The expression to expand is given as:

$(x-3)(x-9)(x-4)$

Let us expand the first two binomials of the given expression using FOIL method.

The FOIL method states that:

$(a + b)(c + d) = ac + ad + bc + bd$

$(x-3)(x-9)=(x\times x)+(x\times -9)+(-3\times x)+(-3\times -9)\\\\(x-3)(x-9)=x^2-9x-3x+27=x^2-12x+27$

Now, let us multiply the result with the remaining binomial. Multiplying each term of the trinomial with each term of the binomial, we get:

$(x^2-12x+27)(x-4)\\\\= (x^2\times x)+ (x^2\times -4)+(-12x\times x)+(-12x\times -4)+(27\times x)+(27\times -4)\\\\=x^3-4x^2-12x^2+48x+27x-108\\\\=x^3-16x^2+75x-108...........(\because-12x^2-4x^2=-16x^2,48x+27x=75x)$

Therefore, the equivalent expression after expanding is given as:

$(x-3)(x-9)(x-4)=x^3-16x^2+75x-108$

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zalisa [80]

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nordsb [41]

Answer:

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