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GrogVix [38]
3 years ago
15

Graph f(x) = (1/3)^x+1​

Mathematics
1 answer:
e-lub [12.9K]3 years ago
4 0

Answer:

The graph is attached below.

Step-by-step explanation:

Given the function

f\left(x\right)\:=\:\left(1/3\right)^x+1

Exponentiation function have a horizontal Asymptotes.

<u />

<u>Finding the horizontal Asymptotes</u>

<u />\mathrm{Exponential\:function\:of\:the\:form}\:f\left(x\right)\:=c\cdot \:n^{ax+b}+k\:<u />

<u />\mathrm{has\:a\:horizontal\:asymptote}\:y=k\:<u />

<u />k=1<u />

<u />\mathrm{The\:horizontal\:asymptote\:is:}<u />

<u />y=1<u />

<u />

<u>Finding y-intercepts</u>

<u />y\mathrm{-intercept\:is\:the\:point\:on\:the\:graph\:where\:}x=0<u />

<u />y=\left(\frac{1}{3}\right)^0+1<u />

<u />\mathrm{Apply\:rule}\:a^0=1,\:a\ne \:0<u />

<u />\left(\frac{1}{3}\right)^0=1<u />

<u />y=1+1<u />

<u />\mathrm{Add\:the\:numbers:}\:1+1=2<u />

<u />y=2<u />

\mathrm{Y\:Intercepts}:\:\left(0,\:2\right)

The graph is attached below.

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<u>x₁ + x₂</u>                             <u>y</u>₁ + <u>y</u>₂<u>
</u>     2      = M                        2     = M
<u>
x + 8</u>                                 <u>y + -2</u><u>
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