Below are the <span> four aspects of society that have benefited from scientific endeavor
</span>
1. information
2. security
3. comfort
4. efficiency
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Answer: 4x²-y²
Explanation:
FORMULA
a²-b²=(a+b)(a-b)
-----------------------------
(a+b)(a-b)=a²-b²
(2x+y)(2x-y)=(2x)²-(y)²
=4x²-y²
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Answer:
72.53 mi/hr
Explanation:
From the question given above, the following data were obtained:
Vertical distance i.e Height (h) = 8.26 m
Horizontal distance (s) = 42.1 m
Horizontal velocity (u) =?
Next, we shall determine the time taken for the car to get to the ground.
This can be obtained as follow:
Height (h) = 8.26 m
Acceleration due to gravity (g) = 9.8 m/s²
Time (t) =?
h = ½gt²
8.26 = ½ × 9.8 × t²
8.26 = 4.9 × t²
Divide both side by 4.9
t² = 8.26 / 4.9
Take the square root of both side by
t = √(8.26 / 4.9)
t = 1.3 s
Next, we shall determine the horizontal velocity of the car. This can be obtained as follow:
Horizontal distance (s) = 42.1 m
Time (t) = 1.3 s
Horizontal velocity (u) =?
s = ut
42.1 = u × 1.3
Divide both side by 1.3
u = 42.1 / 1.3
u = 32.38 m/s
Finally, we shall convert 32.38 m/s to miles per hour (mi/hr). This can be obtained as follow:
1 m/s = 2.24 mi/hr
Therefore,
32.38 m/s = 32.38 m/s × 2.24 mi/hr / 1 m/s
32.38 m/s = 72.53 mi/hr
Thus, the car was moving at a speed of
72.53 mi/hr.
Heat required to decrease the temperature of body is given as
here given that
now by above equation
now in order to evaporate water the heat is given as
so 97 g of water will evaporate from the body
<span>D. The speed of light, traveling in a vacuum, will not change if the light source is moving.
The speed of light in a vacuum is always constant regardless of the speed the source or you are travelling at.</span>
