<span>If you are looking to get an object up the highest, shoot it straight up. If you want to go for a specific horizontal displacement, use the range equation. R = v2sin(twice the launch angle)/ g. g is the gravitaional constant, 9.8 meters per second. Use degrees for the angle. v is the launch velocity. R is the horizontal displacement. This formula only works if your start altitude and end altitude are the same, i.e. you must shoot over a level field.
it depends on the gravitational force of attraction of earth and air resistance.
if we are neglecting air resistance, the max.horizontal distance is according to this formulae,
V0/2 * sin (2theta)
where V0 is the initial velocity
theta is the angle with x axis and the projection.
There are a number of ways that you could find a horizontally displaced object. You could for example just look.</span>
Answer:
always same
Explanation:
velocity and speed are same upto some extend but velocity is vector while speed is scalar quantity
Answer:
its 1st one
the relative strength with which an element attracts electrons in a chemical bond
Answer:
The acceleration of proton is 5.56 x 10^10 m/s^2 .
Explanation:
initial velocity, u = 0
Electric field, E = 580 N/C
final speed, v = 10^6 m/s
(a) Let the acceleration is a.
According to the Newton's second law
F = m a = q E
where, q is the charge of proton and m is the mass.
