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Andru [333]
2 years ago
11

Which imaging technique uses x-rays to make cross-sectional images of the body? mri ct scan x-ray imaging ultrasound

Physics
1 answer:
Vitek1552 [10]2 years ago
5 0

Computed tomography (CT) is an imaging tool that combines x-rays with computer technology to produce a more detailed, cross-sectional image of your body.

<h3>What is CT-Scane?</h3>

Computed tomography (CT) scan is a useful diagnostic tool for detecting diseases and injuries.

Computed tomography (CT) is an imaging tool that combines x-rays with computer technology to produce a more detailed, cross-sectional image of your body.

It uses a series of X-rays and a computer to produce a 3D image of soft tissues and bones.

CT is a painless, noninvasive way for your healthcare provider to diagnose conditions.

A CT scan lets your doctor see the size, shape, and position of structures that are deep inside your body, such as organs, tissues, or tumors.

Hence Computed tomography (CT) is an imaging tool that combines x-rays with computer technology to produce a more detailed, cross-sectional image of your body.

To know more about CT-scane follow

brainly.com/question/1524856

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If the hiker starts climbing at an elevation of 350 ft, what will their change in gravitational potential energy be, in joules,
Kitty [74]

Answer:

352,088.37888Joules

Explanation:

Complete question;

A hiker of mass 53 kg is going to climb a mountain with elevation 2,574 ft.

A) If the hiker starts climbing at an elevation of 350 ft., what will their change in gravitational potential energy be, in joules, once they reach the top? (Assume the zero of gravitational potential is at sea level)

Chane in potential energy is expressed as;

ΔGPH = mgΔH

m is the mass of the hiker

g is the acceleration due to gravity;

ΔH is the change in height

Given

m = 53kg

g = 9.8m/s²

ΔH = 2574-350 = 2224ft

since 1ft = 0.3048m

2224ft = (2224*0.3048)m = 677.8752m

Required

Gravitational potential energy

Substitute the values into the formula;

ΔGPH = mgΔH

ΔGPH = 53(9.8)(677.8752)

ΔGPH = 352,088.37888Joules

Hence the gravitational potential energy is 352,088.37888Joules

7 0
2 years ago
A 3.0N force to the right acts on a 0.5kg object at rest during a time interval of 4.0 seconds .What is the velocity of the obje
monitta

Answer:

24 m/s

Explanation:

Applying Newton's second law of motion,

F = ma................ Equation 1

Where F = force acting on the object, m = mass of the object a = acceleration of the object.

First we calculate for a.

make a the subject of the formula in equation 1 above

a = F/m............... Equation 2

Given: F = 3 N, m = 0.5 kg.

Substitute into equation 2

a = 3/0.5

a = 6 m/s²

Secondly we calculate the velocity by using,

v = u+at................... Equation 3

Where v = Final velocity of the object, u = initial velocity of the object, t = time interval

Given: u = 0 m/s (at rest), a = 6 m/s², t = 4 s

Substitute into equation 3

v = 0+6(4)

v = 24 m/s

5 0
3 years ago
Read 2 more answers
A 9V battery is directly connected to each of 3 LED bulbs. Select the statement that accurately describes this circuit.
dem82 [27]

Answer:

where are the statements?

Explanation:

8 0
3 years ago
There are screws all around you. Name five examples of screws that you see in everyday life? Think broadly!
Ira Lisetskai [31]

Answer:

Some examples of the uses of a screw are in a jar lid, a drill, a bolt, a light bulb, faucets, bottle caps and ball point pens.

Explanation:

3 0
2 years ago
A uniform rod of length 50cm and mass 0.2kg is placed on a fulcrum at a distance of 40cm from the left end of the rod. At what d
oksano4ka [1.4K]

Answer:

x = 45 cm

Explanation:

Given that,

The length of a rod, L = 50 cm

Mass, m₁ = 0.2 kg

It is at 40cm from the left end of the rod.

We need to find the distance from the left end of the rod should a 0.6kg mass be hung to balance the rod.

The centre of mass of the rod is at 25 cm.

Taking moments of both masses such that,

15\times 0.2=x\times 0.6\\\\x=\drac{3}{0.6}\\\\x=5\ cm

The distance from the left end is 40+5 = 45 cm.

Hence, at a distance of 45 cm from the left end it will balance the rod.

5 0
2 years ago
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