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3 years ago

Which imaging technique uses x-rays to make cross-sectional images of the body? mri ct scan x-ray imaging ultrasound

1 answer:

5 0

Computed tomography (CT) is an imaging tool that combines x-rays with computer technology to produce a more detailed, cross-sectional image of your body.

<h3>What is CT-Scane?</h3>

Computed tomography (CT) scan is a useful diagnostic tool for detecting diseases and injuries.

Computed tomography (CT) is an imaging tool that combines x-rays with computer technology to produce a more detailed, cross-sectional image of your body.

It uses a series of X-rays and a computer to produce a 3D image of soft tissues and bones.

CT is a painless, noninvasive way for your healthcare provider to diagnose conditions.

A CT scan lets your doctor see the size, shape, and position of structures that are deep inside your body, such as organs, tissues, or tumors.

Hence Computed tomography (CT) is an imaging tool that combines x-rays with computer technology to produce a more detailed, cross-sectional image of your body.

To know more about CT-scane follow

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what would be the time of flight, maxiumum height and horizontal range of the football was kicked from the floor? if a field goa

Tamiku [17]

Answers:

a) 3.511 s

b) 15.1062 m

c) 86.281 m

Explanation:

Assuming the initial velocity of the ball is $V_{o}=30 m/s$ and the angle $\theta=30\°$ , we have the following data:

$d=40 yards=36.58 m$ the distance between the football player and the the goal post

$H=10 ft=3.084 m$ the height of the goal post

Now, this can be solved with the following equations related to parabolic motion:

$t_{flight}=\frac{2V_{o} sin \theta}{g}$ (1)

$y_{max}=y_{o}+V_{o}sin \theta \frac{t_{flight}}{2}-\frac{g}{2}(\frac{t_{flight}}{2})^{2}$ (2)

$x=V_{o}cos\theta t_{flight}$ (3)

Where:

$t_{flight}$ is the time of flight

$g=9.8 m/s^{2}$ is the acceleration due gravity

$y_{max}$ is the maximum height, when the time is half the time of flight $t_{flight}$

$y_{o}=0 m$ is the initial height

$x$ is the horizontal range

Knowing this, let's begin with the answers:

<h3>a) Time of flight</h3>

We will use equation (1):

$t_{flight}=\frac{2(30 m/s) sin(30\°)}{9.8 m/s^{2}}$ (4)

$t_{flight}=3.511 s$ (5)

<h3>b) Maximum height</h3>

In this case, we have to use equation (2) and substitute the $t_{flight}$ calculated in (5):

$y_{max}=(30 m/s) sin(30\°) \frac{3.511 s}{2}-\frac{9.8 m/s^{2}}{2}(\frac{3.511 s}{2})^{2}$ (6)

$y_{max}=15.1062 m$ (7)

<h3>c) Horizontal range</h3>

Let's use equation (3):

$x=(30m/s)cos(30\°) (3.511 s)$ (8)

$x=86.281 m$ (9)

Since the maximum height and the horizontal range of the ball are greater than $d$ and $H$ , we can say the kicker is able to make the field goal.

5 0

3 years ago

Read 2 more answers

What is a magnetic field? how could you visualize one?

nasty-shy [4]

Answer:

A magnetic field is what causes gravity basically

Explanation:

To visualize a magnetic field think of 2 ovals on the opposite side of each-other, like one oval on the top of a circle and one on the bottom, that's how id visualize it

8 0

3 years ago

Anthony and Maelynn are watching a football game outside on a sunny day. Anthony is wearing a black shirt and Maelynn is wearing

melomori [17]

Answer: Anthony will be warmer after the game.

Explanation :

Anthony and Maelynn are watching a football game outside on a sunny day. Anthony is wearing a black shirt and Maelynn is wearing a white shirt. Anthony will be warmer after the game. The black color is a good absorber of radiation and a bad reflector.

The black color absorbs heat until a thermal equilibrium is attained. So, it is advisable to wear cotton clothes in summers not dark colored clothes.

7 0

3 years ago

Read 2 more answers

Two blocks with the same weight but different dimensions are floating in water at different levels.

fredd [130]

Answer:

(ii) less than

Explanation:

The blocks has the same mass. So, the buoyant force depends only on the volume of the displaced fluid. Since block A has a smaller volume than block B, it displaces a smaller amount of fluid. Therefore the bouyant force exerted by water is less in block A than in block B.

6 0

4 years ago

For how long a time must a tow truck pull with a force of 550N on a stalled 1200kg car to give it a forward velocity of 2.0m/s?

horsena [70]

Answer:

4.36 seconds

Explanation:

According to the question;

Force is 550 N
Mass of the car is 1200 kg
Velocity of the car is 2.0 m/s

We are needed to find the time the car must the tow track pull the car.

From Newton's second law of motion;
Impulsive force, F = Mv÷t , where m is the mass, v is the velocity and t is the time.

Rearranging the formula;

t = mv ÷ F

Thus;

Time = (1200 kg × 2.0 m/s²) ÷ 550 N

= 4.36 seconds

Thus, the time needed to pull the car is 4.36 seconds

5 0

3 years ago