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3 years ago

Which imaging technique uses x-rays to make cross-sectional images of the body? mri ct scan x-ray imaging ultrasound

1 answer:

5 0

Computed tomography (CT) is an imaging tool that combines x-rays with computer technology to produce a more detailed, cross-sectional image of your body.

<h3>What is CT-Scane?</h3>

Computed tomography (CT) scan is a useful diagnostic tool for detecting diseases and injuries.

Computed tomography (CT) is an imaging tool that combines x-rays with computer technology to produce a more detailed, cross-sectional image of your body.

It uses a series of X-rays and a computer to produce a 3D image of soft tissues and bones.

CT is a painless, noninvasive way for your healthcare provider to diagnose conditions.

A CT scan lets your doctor see the size, shape, and position of structures that are deep inside your body, such as organs, tissues, or tumors.

Hence Computed tomography (CT) is an imaging tool that combines x-rays with computer technology to produce a more detailed, cross-sectional image of your body.

To know more about CT-scane follow

brainly.com/question/1524856

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The electron in a ground-state h atom absorbs a photon of wavelength 97. 25 nm. to what energy level does the electron move?

Alecsey [184]

The electron in a ground-state H atom absorbs a photon of wavelength 97. 25 nm. Energy level till where the electron move is 4

Rydberg's equation is formula which signifies relation of wavelength of incident photon and the energy level.

Rydberg's equation is used to find out the relation between the wavelength and the Energy Levels:

1/λ = RZ² (1/n₁² - 1/n₂²)

where, λ is wavelength = 97.25 nm

R is the Rydberg constant = 1.0967 × 10⁷ m

n₁ is the initial energy level i.e. the Ground state, n₁ = 1

n₂ is the higher energy level

On substitution of the above value:

1/97.25 × 10⁻⁹ = 1.0967 × 10⁷ ( 1 - 1/n₂²)

On solving,

⇒ n₂ = 4

Hence, the higher energy level is 4

Learn more about Energy Level here, brainly.com/question/17396431

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5 0

2 years ago

If this wave has frequency of 15 hz. what is the wavelength of that wave ?

Aneli [31]

Do you have any other information? Like the velocity of the wave?

4 0

4 years ago

The maximum lift-to-drag ratio of the World War I Sopwith Camel was 7.7. If the aircraft is in flight at 5000 ft when the engine

andre [41]

The related concepts to solve this problem is the Glide Ratio. This can be defined as the product between the height of fall and the lift-to-drag ratio. Mathematically, this expression can be written as,

$R = h (\frac{L}{D})_{max}$

Replacing,

$R = 5000ft (7.7)$

$R = 38500ft$

Converting this units to miles.

$R = 38500ft (\frac{1mile}{5280ft})$

$R = 7.2916miles$

Therefore the glide in terms of distance measured along the ground is 7.2916miles

3 0

4 years ago

A 2.72 A current flows through a wire for

agasfer [191]

Current=2.72A=I
Time=t=9.88s
Charge=Q

$\\ \rm\longmapsto I=\dfrac{Q}{t}$

$\\ \rm\longmapsto Q=It$

$\\ \rm\longmapsto Q=2.72\times 9.88$

$\\ \rm\longmapsto Q=26.87C$

8 0

3 years ago

Steam is to be condensed on the shell side of a heat exchanger at 150 oF. Cooling water enters the tubes at 60 oF at a rate of 4

zalisa [80]

Answer:

a. 572Btu/s

b.0.1483Btu/s.R

Explanation:

a.Assume a steady state operation, KE and PE are both neglected and fluids properties are constant.

From table A-3E, the specific heat of water is $c_p=1.0\ Btu/lbm.F$ , and the steam properties as, A-4E:

$h_{fg}=1007.8Btu/lbm, s_{fg}=1.6529Btu/lbm.R$

Using the energy balance for the system:

$\dot E_{in}-\dot E_{out}=\bigtriangleup \dot E_{sys}=0\\\\\dot E_{in}=\dot E_{out}\\\\\dot Q_{in}+\dot m_{cw}h_1=\dot m_{cw}h_2\\\\\dot Q_{in}=\dot m_{cw}c_p(T_{out}-T_{in})\\\\\dot Q_{in}=44\times 1.0\times (73-60)=572\ Btu/s$

Hence, the rate of heat transfer in the heat exchanger is 572Btu/s

b. Heat gained by the water is equal to the heat lost by the condensing steam.

-The rate of steam condensation is expressed as:

$\dot m_{steam}=\frac{\dot Q}{h_{fg}}\\\\\dot m_{steam}=\frac{572}{1007.8}=0.5676lbm/s$

Entropy generation in the heat exchanger could be defined using the entropy balance on the system:

$\dot S_{in}-\dot S_{out}+\dot S_{gen}=\bigtriangleup \dot S_{sys}\\\\\dot m_1s_1+\dot m_3s_3-\dot m_2s_2-\dot m_4s_4+\dot S_{gen}=0\\\\\dot m_ws_1+\dot m_ss_3-\dot m_ws_2-\dot m_ss_4+\dot S_{gen}=0\\\\\dot S_{gen}=\dot m_w(s_2-s_1)+\dot m_s(s_4-s_3)\\\\\dot S_{gen}=\dot m c_p \ In(\frac{T_2}{T_1})-\dot m_ss_{fg}\\\\\\\dot S_{gen}=4.4\times 1.0\times \ In( {73+460)/(60+460)}-0.5676\times 1.6529\\\\=0.1483\ Btu/s.R$

Hence,the rate of entropy generation in the heat exchanger. is 0.1483Btu/s.R

4 0

4 years ago